The midsegments of ABC are shown. AB = 14, QS = 7, and m∠BAC = 58°. What is m∠BCA? Enter your answer in the box.
1 answer:
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Solution :
The data is normally distributed.
The standard deviation is 18 days
Here the data is normally distributed and 54 days is 3 days of standard deviation.
Therefore, the percentage of the births that would be within the 54 days of the mean
length is given by :
= P( -3 < Z < 3)
= 0.9544
= 95 %
Therefore, about 95% of the births would be within 54 days of the men
length.