CAN SOMEONE PLEASE HELP ME I WILL MARK YOU AS BRAINLIEST

Chemistry

1 answer:

Komok [63]3 years ago

3 0

Explanation:

$2H_2O_2 \rightarrow 2H_2O + O_2$

First convert the amount of water into moles:

360 g H2O × $\left(\dfrac{1\:\text{mol}H_2O}{18.015\:\text{g}H_2O}\right)$

$= 20. \:\text{mol}H_2O$

Now let's calculate the number of moles of O2 gas produced.

20 mol H2O × $\left(\dfrac{1\:\text{mol}O_2}{2\:\text{mol}H_2O}\right)=10\:\text{mol}O_2$

The volume of gas at 10°C and 5 atm can be found using the ideal gas law:

$PV=nRT$

$V= \dfrac{nRT}{P}$

$= \dfrac{(10)(0.082)(283)}{(5)}=46.4\:L$

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Which of the following is most likely to form multiple (double or triple) bonds? 1. Li 2. Cl 3. N 4. H 5. F

alukav5142 [94]

Answer: Option (3) is the correct answer.

Explanation:

Atomic number of lithium is 3 and its electronic distribution is 2, 1. So, to attain stability it will loose an electron and hence, it forms a single bond.

Atomic number of chlorine is 17 and it has 7 valence electrons. Hence, in order to attain stability it will gain one electron and therefore, it forms a single bond only.

Atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Therefore, to attain stability it needs to gain 3 more electrons. Hence, a nitrogen atom is able to form a triple bond and also it is able to form a double bond.

Hydrogen has atomic number 1 and it attains stability by gaining one electron. Therefore, a hydrogen atoms always forms a single bond.

Atomic number of fluorine is 9 and its electronic distribution is 2, 7. To complete its octet it needs to gain one electron. Hence, a fluorine atom always forms a single bond.

Thus, we can conclude that out of the given options nitrogen is most likely to form multiple (double or triple) bonds.

3 0

3 years ago

2 Calculate What is the density of a liquid with a mass of 17.4g<br> and a volume of 20 mL?

jolli1 [7]

Answer:

P= 0.87g/mL or 0.87g/cm^3

Explanation:

P=m/v

P=density

P=17.4g/20mL

P= 0.87g/mL