Question

CAN SOMEONE PLEASE HELP ME I WILL MARK YOU AS BRAINLIEST

Answer 1

Explanation:

$2H_2O_2 \rightarrow 2H_2O + O_2$

First convert the amount of water into moles:

360 g H2O × $\left(\dfrac{1\:\text{mol}H_2O}{18.015\:\text{g}H_2O}\right)$

$= 20. \:\text{mol}H_2O$

Now let's calculate the number of moles of O2 gas produced.

20 mol H2O × $\left(\dfrac{1\:\text{mol}O_2}{2\:\text{mol}H_2O}\right)=10\:\text{mol}O_2$

The volume of gas at 10°C and 5 atm can be found using the ideal gas law:

$PV=nRT$

$V= \dfrac{nRT}{P}$

$= \dfrac{(10)(0.082)(283)}{(5)}=46.4\:L$