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DIA [1.3K]
3 years ago
14

Which is that law?????????

Chemistry
1 answer:
algol [13]3 years ago
3 0

Answer:

I hope you understand and happy

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Actual value= -273 Experimental value= -274
Maurinko [17]

Answer:

<h2><u><em>When measuring data, the result often varies from the true value. Error can arise due to many different reasons that are often related to human error, but can also be due to estimations and limitations of devices used in measurement. Regardless, in cases such as these, it can be valuable to calculate the percentage error. The computation of percentage error involves the use of the absolute error, which is simply the difference between the observed and the true value.</em></u></h2>

Explanation:

4 0
3 years ago
The melting point of aluminum is about 660 °C. How many degrees above the boiling point of water is this temperature?
Arte-miy333 [17]
560 degrees above water
8 0
3 years ago
What is the pH of 1.0M HI solution?
ozzi

Answer:

0

Explanation:

Since HI is a strong acid, the amoung of Hydrogen ions produced by it will be the same molar as the reactant. The negative log of the concentration will reveal that the pH is 0.

7 0
3 years ago
Read 2 more answers
Compare and contrast the functions of each of the following types of flasks: filter, Erlenmeyer, volumetric.
harkovskaia [24]
The Erlenmeyer Flask was <span>introduced in 1861 by German chemist </span>Emil Erlenmeyer and is shaped like a cone. This has a triangular shape and mouth wide for it to be easier to pour and store liquids. The Volumetric flask<span> is used for preparing liquids with volumes of high precision. It has a </span>pear-shaped body and a long neck with a circumferential fill line. The Filter Flask is also known as the <span>A Büchner </span><span>flask. It is like the Erlenmeyer but this one is thick-walled and has a special arm in the side. It is used for filtering liquid. </span>
4 0
3 years ago
A piston in a heat engine does 500 joules of work, and 1400 joules of heat are added to the system. Determine the change in inte
san4es73 [151]

Answer : The change in internal energy is, 900 Joules.

Solution : Given,

Heat given to the system = +1400 J

Work done by the system = -500 J

Change in internal energy is equal to the sum of heat energy and work done.

Formula used :

\Delta U=q+w

where,

\Delta U = change in internal energy

q = heat energy

w = work done

As per question, heat is added to the system that means, q is positive and work done by the system that means, w is negative.

Now put all the given values in the above formula, we get

\Delta U=(+1400J)+(-500J)=900J

Therefore, the change in internal energy is 900 J.

The change in internal energy depends on the heat energy and work done. As we will change in the heat energy and work done, then changes  will occur in the internal energy. Hence, the energy is conserved.

8 0
3 years ago
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