Answer:
Fluorine has seven electrons in 2p-subshell whereas chlorine has seven electrons in its 3p-subshell. 3p-subshell is relatively larger than 2p-subshell. Therefore, repulsion among the electrons will be more in the 2p-shell of fluorine than 3p-subshell in chlorine. Due to the smaller size and thus, the greater electron-electron repulsions, fluorine will not accept an incoming electron with the same as chlorine.
Answer:
Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.
Explanation:
Paso 1: Escribir la ecuación balanceada
BrF₃ (g) ⇌ BrF(g) + F₂(g) Kp(T) = 64,0
Paso 2: Calcular el cociente de reacción (Qp)
Qp = pBrF × pF₂ / pBrF₃
Qp = 1,50 × 2,00 / 0,0150 = 200
Paso 3: Sacar una conclusión
Dado que Qp > Kp, la reacción se desplazará hacia la izquierda para alcanzar el equilibrio, es decir, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.
Answer:copper(II) sulfate, CuSO4> 2-pentanol, C5H11OH> methane, CH4>propane, C3H8.
Explanation:
Solubility depends on the ability of solute to interact effectively with a solvent. If water is the solvent, it interacts effectively with ionic substances. copper II sulphate is ionic and will be the most soluble in water, 2-pentanol, will interact effectively with water via hydrogen bonding. Between methane and propane, methane will interact better with water since it has a shorter alkyl chain than propane
C) because the sun rays are converted into electricity by exciting electrons into silicon cells etc etc..
