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Daniel [21]
3 years ago
12

The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical trial, results co

uld be analyzed with a formal hypothesis test with the alternative hypothesis of p>0.5, which corresponds to the claim that the method increases the likelihood of having a girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the method, which of the following P-values would you prefer: 0.999, 0.5, 0.95, 0.05, 0.01, 0.001? Why? The P-value of (0.999.05.095.005-001.0001) 2 is preferred because it corresponds to the sample evidence that most strongly supports the (null/ altenative)? hypothesis that the method (is/ is not)? effective.
Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

0.001

Step-by-step explanation:

Ericsson is claimed to increase the likelihood of a baby girl ;

Given the alternative hypothesis to buttress this claim :

HA : p>0.5

In other to establish the success of Ericsson's claim, then there must be significant evidence to reject the Null hypothesis ; hence adopt the alternative.

To Do this, we need a very small Pvalue ; such that it will be lesser than the α - value in other to reject the Null and adopt the alternative.

Recall ;

Pvalue < α ; We reject the Null

Therefore, from the options, we choose the smallest Pvalue as we want the Pvalue to be as small as possible.

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Hello, I would like help with this, please.
disa [49]

Answer:

slope= 1/2

c

Step-by-step explanation:

part a)

m= 4 - 0 / 8 - 0

= 1/2

5 0
3 years ago
A train has 6 passenger cars and each car has 4 columns of seats and each column holds 50 passengers. If one of the cars has 25
Tema [17]
Given:
The train has 6 passenger cars
Each car has 4 columns
And 1 column hold 50 passengers

So, total of seats will be = 6 * 4 * 50 = 1200

Now, there are 25 empty seats, 

therefore the correct equation will be : 

Number of seats per car: 4 × 50 = 200

Total number of seats: 200 × 6 = 1,200

Number of passengers: 1,200 − 25 = p




6 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Identify the decimals labeled with the letters A, B, and C on the scale below. Letter A represents the decimal Letter B represen
Yuliya22 [10]

10 divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$

A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$

similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$

and B is $390.3$

8 0
3 years ago
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