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Daniel [21]
3 years ago
12

The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical trial, results co

uld be analyzed with a formal hypothesis test with the alternative hypothesis of p>0.5, which corresponds to the claim that the method increases the likelihood of having a girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the method, which of the following P-values would you prefer: 0.999, 0.5, 0.95, 0.05, 0.01, 0.001? Why? The P-value of (0.999.05.095.005-001.0001) 2 is preferred because it corresponds to the sample evidence that most strongly supports the (null/ altenative)? hypothesis that the method (is/ is not)? effective.
Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

0.001

Step-by-step explanation:

Ericsson is claimed to increase the likelihood of a baby girl ;

Given the alternative hypothesis to buttress this claim :

HA : p>0.5

In other to establish the success of Ericsson's claim, then there must be significant evidence to reject the Null hypothesis ; hence adopt the alternative.

To Do this, we need a very small Pvalue ; such that it will be lesser than the α - value in other to reject the Null and adopt the alternative.

Recall ;

Pvalue < α ; We reject the Null

Therefore, from the options, we choose the smallest Pvalue as we want the Pvalue to be as small as possible.

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