Convert the following number from scientific notation to standard notation:<br> 7.80 x 105

Consider the statement below.

Vilka [71]

Answer:

C

Explanation:

Took the Edgenuity test

3 0

3 years ago

What do you think would happen to reef dwellers (e.g., coral, parrot fish, sea cucumbers) if the algae were not able to photosyn

Dafna1 [17]

Photosynthesis is the process wherein energy from sunlight is used to catalyze the reaction converting carbon dioxide and water to glucose. If the algae were deprived of the capability to photosynthesize then they will not be able to derive the energy from the sun into usable energy in the form of glucose and eventually will lead to death of the algae. Algae, being in the bottom of the food chain, is the primary source of food, therefore energy (in the form of sugars) of reef dwellers. Cellular respiration is the process where energy stored in sugars such as glucose is converted into usable energy in the form of adenosine triphosphate and waste products such as carbon dioxide and water is produced. Without the source of energy (algae), the reef dwellers will eventually starve and die.

8 0

4 years ago

--IF YOU PUSH SOMETHING WITH STRONG FORCE DOES THE MOTION GO SLOWER

zaharov [31]

Answer:

i dont think so

Explanation:

is there a image to explain this ? if so it would help ALOT

8 0

2 years ago

Read 2 more answers

What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10

vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, $\rm pOH = 14 - pH$

The pH of KOH can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the first case, the concentration of the KOH is $1. 87 \times 10^{-13}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times 10^{-13}\;\rm M ]\\\\&= 12.73\end{aligned}$

Hence, the pH of KOH is 12.73.

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pOH of KOH can be calculated by the formula,

$\rm pOH = \rm -log [OH^{-}]$

The hydroxide concentration of the KOH solution is $5. 81 \times 10^{-3}\;\rm M$

Substituting value in the equation:

$\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm M ]\\\\&= 2.24 \end{aligned}$

Hence, the pOH of KOH is 2.24

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The pH of NaCl can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the third case, the concentration of the NaCl is $1. 00\times 10^{-7}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times 10^{-7}\;\rm M ]\\\\&= 7 \end{aligned}$

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

brainly.com/question/13885794

3 0

3 years ago

Categorize the following reaction: C3H8 + O2 ---> CO2 + H2O *

vichka [17]

Answer:

it is a replacement reaction

7 0

3 years ago

Convert the following number from scientific notation to standard notation: 7.80 x 105