Answer:
I agree
Explanation:
For scientists working in classified areas, collaboration with university programs and researchers provides opportunities to expand and strengthen their science through the conduct of peer-reviewed, open literature research.
Answer:
64,433.6 Joules
Explanation:
<u>We are given</u>;
- Volume of water as 220 mL
- Initial temperature as 30°C
- Final temperature as 100°C
- Specific heat capacity of water as 4.184 J/g°C
We are required to calculate the amount of heat required to raise the temperature.
- We know that amount of heat is calculated by;
Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.
Density of water is 1 g/mL
Thus, mass of water is 220 g
ΔT = 100°C - 30°C
= 70°C
Therefore;
Amount of heat, Q = 220g × 4.184 J/g°C × 70°C
= 64,433.6 Joules
Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules
Answer:
what are the items that have been listed?
If you're talking about in an actual sample, you'd need more data like how many moles you have of the reactant or product.
Just in terms of the equation : there are two from the water in the reactant (left) side, and one from the sodium hydroxide and two for the hydrogen gas on the product (right) side, so 2+1+2=5 atoms of hydrogen.
