Answer:
0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
Explanation:
According to reaction, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.
Then 1.8 moles of sulfuric acid will react with:
moles of NaOH.
Molarity of NaOH = 4.0 M
Moles of NaOH= n = 3.6 mol
Volume of NaOH = V
0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
Answer:
The relation between the shielding and effective nuclear charge is given as
where s denote shielding
z_{eff} denote effective nuclear charge
Z - atomic number
Explanation:
shielding is referred to as the repulsion of an outermost electron to the pull of electron from valence shell. Higher the electron in valence shell higher will be the shielding effects.
Effective nuclear charge is the amount of net positive charge that valence electron has.
The relation between the shielding and the effective nuclear charge is given as
wheres denote shielding
z_{eff} denote effective nuclear charge
Z - atomic number