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marshall27 [118]
3 years ago
15

Andrea does not understand why if x is a solution to the equation 3-x=4 then x is also a solution to the equation 12=9-3x. Write

a convincing explanation as to why this is true
Mathematics
1 answer:
Strike441 [17]3 years ago
6 0

Answer:

Both equations are same

Step-by-step explanation:

The reason why this is true is not far fetched

looking at the first equation, we have;

3-x = 4

we can also factorize the second equation to look this way

By this, we shall be having

3(4) = 3(3-x)

By the time we take out the 3 from both sides, we will have the initial equation

So what we are saying is that both equations are the same

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Word problems<br><br>kind of urgent
seraphim [82]
838. = 27x-271.42
+271.42. +271.42
1109.42= 27x
Divide by 27
X= $41.0896 per hour

5. Gross Pay is what you make before they takes taxes and insurance. From your check.
So Net Pay is better because what you actually get.
8 0
3 years ago
At Kroger you can purchase a 20 ounce box of Cinnamon Toast Crunch for $4. What is the Unit Price (Cost per 1 Ounce)?
olga_2 [115]

Answer:

20 cents

Step-by-step explanation:

$4.00 divided by 20 (ounces) is $0.20.

8 0
3 years ago
Read 2 more answers
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
4 years ago
I need some help with this question, I got a different answer.
N76 [4]

Answer:

The median is the middle number.

Step-by-step explanation:

You have to order the numbers from least to greatest, or greatest to least, and choose the number in the middle. Since there is an even number of values, you have to take the mean of the two middle numbers. I hope this helps.

5 0
3 years ago
Hey guys I was just needed assistance with a math question? So (3x-4)(2x-1) is it equal to 6x^2-11x+4 thats is what I got when I
torisob [31]
I got 6x∧2 - 11x + 4
So your answer is correct
Cause I use the box method if that is what u used
4 0
3 years ago
Read 2 more answers
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