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Length and width of rectangle is 15 inches and 6 inches respectively
<h3><u>Solution:</u></h3>Given that area of a rectangle is 90 square inch
Ratio of length to the width = 5: 2.
Need to determine length and width of rectangle.
As ratio of length to the width is 5 : 2
Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.
<em><u>The formula for area of rectangle is given as:</u></em>
Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:
On solving the above expression for x we get
Hence length and width of rectangle is 15 inches and 6 inches.
The new pool is 18.84 feet larger in circumference than the old one.
<u>Explanation:</u>
Given:
Circumference of the pool = 47.1 feet
Diameter of the new pool, d = 21 feet
radius, r = 21/2 feet
Circumference of the new pool = ?
We know:
Circumference = 2πr
where,
r is the radius
On substituting the value:
C =
C = 65.94 feet
The difference in circumference of the two pools = 65.94 - 47.1 feet
= 18.84 feet
Therefore, the new pool is 18.84 feet larger in circumference than the old one.
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