Question

What is the area of triangle GHJ?

Answer 1

We are tasked to solve for the area of the triangle GHJ. The formula for solving the area of a triangle is Area = 1/2bh where b is the base measurement and h is the height measurement.
Based on the attached picture, the following are the measurements:
b = 3 units
h = 4 units

Solving for the area, we have:
Area = 1/2*3*4
Area = 6 squared units

The answer is the letter "B" or the second item in the choices.

Answer 2

Answer:

Option B is correct.

The area of triangle GHJ is, 6 square units.

Explanation:

Given: In ΔGHJ

the coordinates are G=(1,1) , H=(4,1) and J=(4,5).

Now, find the length of GH and HJ by using distance(D) formula for two points $(x_1 ,y_1)$ and $(x_2 ,y_2)$ is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Calculate the length of GH;

GH = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ = $\sqrt{(4-1)^2+(1-1)^2}= \sqrt{(3)^2+(0)^2}=\sqrt{9} =3$ unit

Similarly, for the length of HJ;

HJ = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ = $\sqrt{(4-4)^2+(5-1)^2}= \sqrt{(0)^2+(4)^2}=\sqrt{16} =4$ unit

Using formula for the area of a triangle is

$A=\frac{1}{2}bh$; where b is the base and h is the height.

then; the area of triangle GHJ;  $A=\frac{1}{2} (GH)(HJ)$ where GH represents the base and HJ represents the height.

Substituting the values of GH and HJ in above formula:

$A=\frac{1}{2} \cdot 3 \cdot 4 =3 \cdot 2 =6$ square units.

Therefore, the area of ΔGHJ is, 6 square units.