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pav-90 [236]
3 years ago
6

Which fraction is equal to 5/10

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer: There are a lot of examples of this, but in short, any number that can be written as 1/2 is your answer. Think about it, 5 is half of 10. So that means that 20/40, 6/12, 3/6, 70/140, etc are all equal

Shkiper50 [21]3 years ago
3 0

1/2, 2/4, 3/6, 4/8, 5/10, 6/12, 7/14, 8/16, 9/18, 10/20, 11/22, 12/24, 13/26, 14/28, 15/30, 16/32, 17/34, 18/36, 19/38, 20/40

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Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
PLZ HURRY!!!! 15 POINTS!
Daniel [21]
I think it’s 7.5 minutes
5 0
3 years ago
Read 2 more answers
Opening a daycare regular regulations mandate 35 ft.² of space per child how much floor space will you need for 15 children will
NeTakaya
525 ft.^2 for 15 children. No it will not.
6 0
3 years ago
When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w
deff fn [24]

Answer:

A 90% confidence interval for <em>p</em> will be <u>narrower </u>than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - <em>α</em>) % confidence interval for a population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Here \hat p is the sample proportion.

The margin of error of the confidence interval is:

MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The MOE is dependent on:

  1. Confidence level
  2. Standard deviation
  3. Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645

And the critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for <em>p</em> will be narrower than the 99% confidence interval.

6 0
3 years ago
I need help with part b and A So can anyone tell me how to solve this?
tekilochka [14]
Answer:

A:
You do 65 divided by 25 = 2.6
52 divided by 2.6 = 20

Ryan has 20, so the answer is Ryan.
Hope this helps!
5 0
2 years ago
Read 2 more answers
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