The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
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Answer:
The answer is 10.5
Step-by-step explanation:
The answer should be a :)
Hey!
When you raise a number to a power, you multiply that number by itself. (4^2 = 4 * 4 for example) 1.2 * 1.2 = 1.44 That's for the first one.
2^3 + 17 - 3 * 4. ---> 8 + 17 - 3 * 4
8 + 17 - 3 * 4 ---> 8 + 17 - 12
8 + 17 - 12 ---> 25 - 12
25 - 12 ---> 13 Thats for the second one.
9^2 / 3^3 ---> 81/27
81/27 ---> 3 Thats for the third one.
Hope this helps!! ☺♥
Answer:
Answer:
1 notebook = 5.69 + paper 1.39 + dividers 1.45 + 2 pens 2.38 + pencils2.5
13.41 is the answer
Step-by-step explanation:
Step-by-step explanation: