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3 years ago

10

Suppose a line segment whose endpoints are T(x 1 ,y 1 ) and U(x 2 ,y 2 ) is reflected over y=x to create T’U’. The coordinates o

f the image are T’(-4,3) an U’(1,7). What are the values of x 1 x 2 y 1 and y 2?

2 answers:

hodyreva [135]3 years ago

8 0

Answer:

same bro

Step-by-step explanation:

Serjik [45]3 years ago

6 0

Answer:

I have no clue and im a junior im so sorry your teach sucks

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In order to answer his questions, Alonzo decided to get out his set of plastic geometry models. He has a sphere, cone, and cylin

mojhsa [17]

A. If the radius of the sphere is r, what is the height of the cylinder H=4√r

B The volume of the sphere will be V=4πr³

<h3>What is volume?</h3>

Volume is defined as the space occupied by any object in the three-Dimenions. All three parameters are required for the volume like length, width and height of cube or cuboid.

Here for the part A If the radius of the sphere is r, what is the height of the cylinder the solution will be given as:-

The Volume of sphere = Volume of cylinder

4πr³=(π÷4) r²H

H=16r

H=4√r

Hence the height of the cylinder will be H=4√r

B. The volume of the shapes will be given as:-

(1) Volume of cylinder = (π÷4)r²H

Here r= radius of the cylinder

H = height of the cylinder

(2) The Volume of the Sphere=4πr³

Here r= radius of the cylinder

(3) The Volume of cone=(1÷3)πr³l

Here r = radius of the base

l=slant height of the cone

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8 0

3 years ago

What's the slope of a line that passes through (-4,-13) and (19.11)?

tester [92]

Answer:

m=24/23

Step-by-step explanation:

m=11+13/19+4

m=24/23

6 0

3 years ago

Question 1(Multiple Choice Worth 2 points)

dusya [7]

Answer:

6x +47

Step-by-step explanation:

f(x) = 6x + 11

g(x) = x + 6

now f[g(x)]=<em>by</em><em> </em><em>substituting</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>g</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>to</em><em> </em><em>f</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>f[g(x)]</em><em>=</em><em>6</em><em> </em><em>(</em><em>x</em><em>+</em><em>6</em><em>)</em><em>+</em><em>11</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6x</em><em>+</em><em>36</em><em>+</em><em>11</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6x</em><em> </em><em>+</em><em>47</em>

7 0

4 years ago

What can polynomial identities apply to beyond just polynomials?

Nina [5.8K]

One polynomial identity that crops up often in various areas is the difference of squares identity:
A2-b2=(a-b) (a+b)
We meet this in the context of rationalising denominators.

6 0

4 years ago

Mr. Tesoro drew this quadrilateral with two equal sides that meet at a right angle and a pair of equal opposite angles that are

kirill [66]

Answer:

The answer is kite.

Step-by-step explanation:

Well, just looking at the definition of a kite, we can see that it lines up with Mr. Tesoro's description and drawing of the quadrilateral. A kite has one right angle that meets up witht two equal lines. The opposite pair of lines, that are much longer, don't meet up to be a right angle. The definitions line up, so there's your match; the anser is kite.

5 0

4 years ago