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fenix001 [56]
3 years ago
10

Suppose a line segment whose endpoints are T(x 1 ,y 1 ) and U(x 2 ,y 2 ) is reflected over y=x to create T’U’. The coordinates o

f the image are T’(-4,3) an U’(1,7). What are the values of x 1 x 2 y 1 and y 2?
Mathematics
2 answers:
hodyreva [135]3 years ago
8 0

Answer:

same bro

Step-by-step explanation:

Serjik [45]3 years ago
6 0

Answer:

I have no clue and im a junior im so sorry your teach sucks

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Is 16% of 40 the same as 40% of 60? Explain your reasoning.
o-na [289]
No 16% of 40 is 32/5 where 40%of 60 is 24.
 Hope this helps.
6 0
3 years ago
Read 2 more answers
Solve for this equation. x-2/5=1/5
Studentka2010 [4]

Answer:

3/5   or

0.6

Step-by-step explanation:

You could change these fractions to decimals, but you may not be convinced that the answer you get is the same as just using fractions. I'll start by using fractions.

x - 2/5 = 1/5                        Add 2/5 to both sides

x - 2/5 + 2/5 = 1/5 + 2/5     The left side cancels to 0.

x = 1/5 + 2/5                       The denominators (bottom the fraction) are the same. Just add the tops.

x = (1 + 2)/5

x = 3/5

=======================

If you use your calculator to find 2/5 and 1/5, you can get the same answer as 3/5

2

÷

5

=

0.4

By the same method, 1/5 = 0.2

Substitute into the original equation

x - 0.4 = 0.2                       Add 0.4 to both sides

x - 0.4 +0.4 = 0.2 + 0.4    The left side reduces just to x

x = 0.2 +0.4

x = 0.6

If you let your calculator do the work, like this

3

÷

5              

=

0.6

The answers are the same.

7 0
3 years ago
Read 2 more answers
???????anyone know...
RUDIKE [14]
The answer is:  " 60° " .
__________________________________________________________
     " m∠A = 60° " .
__________________________________________________________
Explanation:
__________________________________________________________

Note:  All triangles, by definition, have 3 (three) sides and 3 (three angles).

The triangle shown (in the "image attached") has three EQUAL side lengths.   Therefore, the triangle shown is an "equilateral triangle" and has 3 (three) equal angles, as well.

All triangles by, definition, have 3 (three) angles that add up to "180° " .

Since each of the 3 (three) angles is equal;  and the three angles are:  

  "∠A" , "∠B" , and "∠C" ;

We can find the measure of "∠A" ; denoted as:  "m∠A" ; as follows:
______________________________________________________
    m∠A  = 180° ÷ 3 = 60° .
______________________________________________________
The answer is:  " 60° " .
______________________________________________________
   m∠A = " 60° " .
______________________________________________________
7 0
3 years ago
What is the difference
Advocard [28]

Answer:

what is question of this you asked

3 0
3 years ago
Solve for x. Round to the nearest tenth, if necessary.
e-lub [12.9K]

Answer:

\boxed {\boxed {\sf x \approx 1.9}}

Step-by-step explanation:

We are asked to find x, a missing side in a triangle.

This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:

  • sinθ= opposite/hypotenuse
  • cosθ= adjacent/hypotenuse
  • tanθ= opposite/adjacent

Examine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is <u>opposite</u> angle S. Side QS, measuring 2.3, is the <u>hypotenuse</u> because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.

sin \theta = \frac {opposite}{hypotenuse}

  • θ= 54
  • opposite= x
  • hypotenuse = 2.3

sin (54)= \frac{ x}{2.3}

We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3

2.3* sin (54)= \frac{x}{2.3}*2.3

2.3* sin (54)=x

2.3*0.8090169944=x

1.860739087 =x

Round to the nearest tenth. The 6 in the hundredth place to the right tells us to round the 8 up to a 9.

1.9 \approx x

x is approximately <u>1.9</u>

7 0
3 years ago
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