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Vlad [161]
3 years ago
7

Whats 4+4 i need help. its really hard

Mathematics
2 answers:
pentagon [3]3 years ago
4 0
4+4 is 8 lol thanks for the answer
djverab [1.8K]3 years ago
4 0

Answer:

The answer for 4+4 is 8

Step-by-step explanation:

can u mark brainliest please

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According to the table below, what is the domain of the data?
maxonik [38]

Answer:

796037854

Step-by-step explanation:

thvjjhxugnvfcx ghrfhjb gbhxjbjg

3 0
3 years ago
Using the digits 0 to 9 ​
Gre4nikov [31]

Supplementary Angles:

\boxed{100°} and \boxed{80°}

Arithmetically speaking, the closest 2 supplementary angles can get (in 3 and 2 digits respectively) is the upwritten.

Complementary Angles:

\boxed{45°} and \boxed{45°}

Simply, in this case, for angles to be numerically as close as possible - make both the angles 45°.

8 0
2 years ago
01. En una piscigranja el 30% de boquichicos es el 20% del número de carachamas. Si sólo hay boquichicos y carachamas. ¿Qué porc
Simora [160]

Answer:

0.1. B) 50%

0.2 A) Psicología

Step-by-step explanation:

01. Dejemos que 'x' e 'y' representen el porcentaje de boquichicos y carachamas en la piscifactoría, tenemos;

Dado que el 30% de los boquichicos es el 20% del número de carachamas

30% x = 20% y

∴ 0.3 · x = 0.2 · y

Por lo tanto, tenemos;

x / y = 0,2 / 0,3 = 2/3

Por lo tanto, por cada 100% de pescado, tenemos;

x + y = 100%

x = 2/3 · y

2/3 · y + y = 100%

5 · años / 3 = 100

y = 100 × 3/5 = 60%

El porcentaje de carachamas en la finca, y = 60%

∴ x = 100% - y = 100% - 60% = 40%

El porcentaje de boquichicos en la finca, x = 40%

Por lo tanto, tenemos el 80% del pescado en la granja, obtenemos;

Si hay 100 peces en la granja, 80% = 80 peces

Pero el número de los 100 peces que son boquichicos en la granja = 40% × 100 = 40 peces

Por lo tanto, los boquichicos son la mitad del 80% del número de peces o el 50% de los peces en la piscifactoría.

La opción correcta es;

B) 50%

02. Tenemos;

El costo de un libro de psicología> El costo de un libro en inglés

El costo de un libro de matemáticas> El costo de un libro de historia

El costo de un libro de psicología> El costo de un libro de matemáticas

Por lo tanto, tenemos;

El costo de un libro de psicología> El costo de un libro de matemáticas> El costo de un libro de historia

∴ El libro de Psicología es más caro que todos los demás libros y, por tanto, es el libro más caro

La opción correcta es;

A) Psicología

3 0
3 years ago
Silcon-28 has a mass-per-nucleon of 1.003 amu. Iron-56 has a mass-per-nucleon of 0.99723 amu. Cadmium-112 has a mass-per-nucleon
Ber [7]

Answer:

no

Step-by-step explanation:

4 0
3 years ago
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
3 years ago
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