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Molodets [167]
3 years ago
13

Please help me im cryinggg

Mathematics
1 answer:
sammy [17]3 years ago
4 0

Answer:

Do you still need the help

Step-by-step explanation:

ghsrgs

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Find the point-slope equation of the line with slope -3 that passes<br> through the point (2, -10).
MatroZZZ [7]

Answer:

Step-by-step explanation

(-y-y1)/(x-x1)= m

y-(-10)/(x-2)= -3

y= -3x -4

4 0
2 years ago
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What is the REMAINDER of 15,908 divided by 13?
stellarik [79]
The remainder is 9........
6 0
2 years ago
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Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
Josephine has a rectangular garden with an area of 2x2
sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

(2x - 3) * (x + 2) = 2x^2 + x - 6

Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

6 0
3 years ago
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How many yards off the line of scrimmage does the pass rusher need to line up?
stich3 [128]

The pass rusher, which is typically line up on the line of scrimmage.

Have a Great Day :)

3 0
2 years ago
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