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2 years ago

I need help with number 6

Mathematics

1 answer:

vodka [1.7K]2 years ago

3 0

Answer:

the value of x is 18........

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True or False:

atroni [7]

Answer:

no it can't because

Step-by-step explanation:

coz the sum of any two angle should be greater than 3rd side

13 + 5 = 18 which is greater than 7
13 + 7 = 20 which is greater than 5
5 + 7 = 12 which is not greater than 13

so triangle cant be made

3 0

3 years ago

Ratio equivalent to 3 : 4

lana66690 [7]

A ratio equivalent to 3:4 is 6:8

4 0

3 years ago

BIG POINTS!!! (p-.20 p=new price.) "Natasha bought a racket that was marked down 20%" (my equation was in first parenthesis) If

MariettaO [177]

120-(120*20%) = 120-24 = 96
Natasha paid $96.
0.8p represents how much the price was when Natasha paid.

3 0

3 years ago

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago

Elise has to use the information given below to find the original number. Write an equation to represent the situation. What is

lilavasa [31]

Let x= original number
equation: 2x+24=2/7 x
move 2x over to the other side of the equation to get 24=-12/7 x. Then, multiply both sides of the equation by -7/12 to isolate the variable.
The final answer should be x=-14

3 0

3 years ago