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Nikolay [14]
2 years ago
13

Ave: 7k- 14 = 42 How do you solve it

Mathematics
2 answers:
Mashutka [201]2 years ago
5 0

Answer:

you have to isolate the variable

Step-by-step explanation:

7k-14=42

+14    +14

7k=56

7k/7+56/7

k=8

: )

Misha Larkins [42]2 years ago
4 0

Answer:

Im going to guess k is the unknown

Step-by-step explanation:

7k-14=42

42+14=7k

56=7k

56/7=k

k=8

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Answer:

She is more likely to make a free throw in basketball.

Step-by-step explanation:

This is because 73% is equal to .73 and .72 is equal to 72% so thats more common.

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3 years ago
Which expression is equal to (3x−5)(2x−7)?
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(3x-5)(2x-7)
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According to the Venn diagram below, what is P(A∩B∩C)?
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The upside down U means intersection

A intersect B intersect C is where all 3 circles overlap.

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The decreasing​ population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.
n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing​ population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=-0. 4t^2+128t+1,200

For population to disappear, p =0

-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

7 0
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