Answer:
2m
Step-by-step explanation:
For m, I look for the greatest power of m that is in all of the expressions. Since the first has m^2, the second has m, and the third has m^4, the greatest power of m that is in all expressions is m.
For the number, I look for the greatest factor of 8, 4, and 10. A trick would be to look at the smallest number since the greatest common factor can only be less than or equal to the smallest number. So looking at 4, the factors are 1,2,4. 4 is not a common factor since it does not divide into 10, but 2 is so 2 is the greatest common numerical factor.
Combine 2 and m to get 2m.
I’m assuming what you’re asking here is how to *factor* this expression. For that, let’s rearrange the expression into a more familiar form:
-c^2-4c+21
From here, we’ll factor out a -1 so that we have:
-(c^2+4c-21)
Let’s focus on the quadratic expression inside the parentheses. To find our factors (c + x)(c + y), we’ll need to find two terms x and y that multiply together to make -21 and add together to make 4. It turns out that the numbers -3 and 7 work out perfectly for that purpose (-3 x 7 = -21 and 7 + (-3) = 4), so substituting them in for x and y, we have:
(c + (-3))(c + 7)
(c - 3)(c + 7)
And adding back on the negative from a few steps earlier:
-(c - 3)(c + 7)
nine divided by five to the sixth power is 0.000576
