Answer: p = 2
Step-by-step explanation:
To solve this problem, you first have to add 1 to each side of the equation, leaving you with 2p^2 = 8. Then you divide by 2 on both sides leaving you with p^2 = 4. After that, you take the square root of both sides, and because 4 is a perfect square, you get p = 2 as your final answer.
Answer:
Hi there!
I might be able to help you!
It is NOT a function.
<u>Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function</u>. <u>X = y2 would be a sideways parabola and therefore not a function.</u> Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is <em>not </em>a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.
A relation that is not a function
As we can see duplication in X-values with different y-values, then this relation is not a function.
A relation that is a function
As every value of X is different and is associated with only one value of y, this relation is a function.
Step-by-step explanation:
It's up there!
God bless you!
Answer:
the second one
Step-by-step explanation:
if it is right pls mark brainliest thanks :)
For this case we have:
Let a function of the form 
By definition, to graph
, where
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that 
So, if the black graph is given by
, the red graph is given by: 
Answer:

Option A