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SSSSS [86.1K]
2 years ago
12

What is the equation of the line that passes through the point (-6, -8) and has a slope of 1/3

Mathematics
2 answers:
Papessa [141]2 years ago
5 0

Answer:

x^2 = (28)^2 + (45)^2

= 784 + 2025

= 2809

x = 53

ivanzaharov [21]2 years ago
3 0

Answer <u>(assuming it can be in point-slope form)</u>:

y + 8 = \frac{1}{3} (x+6)

Step-by-step explanation:

With the given information, we can use the point-slope formula, y-y_1 = m (x-x_1), to write the equation of the line. Substitute values for the m , x_1, and y_1 in the formula to do so.

The m represents the slope, so substitute \frac{1}{3} in its place. The x_1 and y_1 represent the x and y values of one point the line intersects, so substitute -6 for x_1 and -8 for y_1. This gives the following answer and equation (just make sure to convert the double negatives into positives:  

y-(-8) = \frac{1}{3} (x-(-6))\\y + 8 = \frac{1}{3} (x+6)

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Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.

(See attachment below for the figure)

m∠CEA = 90°

m∠CEF = m∠CEA + m∠BEF

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Answer:

m∠CEA = 90°

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Step-by-step explanation:

Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.

Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.

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m∠CEA = 90°

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∠AEF is a right angle

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