2Na + 2H₂O ⇒ 2NaOH + H₂
n(Na):n(NaOH)=2:2, n(NaOH)=n(Na)=3mol
m(NaOH)=n·M= 3mol · 40g/mol(molar mass, 23+16+1)=120g.
Answer: 0.664 moles and 65.1 grams EDMENTUM USERS
Explanation: From the equation, we know that 1 mole of calcium phosphate produces 2 moles of phosphoric acid (H3PO4). So, if we know how many moles of calcium phosphate are present in 103 grams of Ca3(PO4)2, we can find the corresponding number of moles of H3PO4 that are produced during the reaction.
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.
Answer is 1.42x10^24
Answer:
14 g.
Explanation:
- From the figure attached:
<em>the solubility of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC is </em><em>(66 g).</em>
When beaker containing 80 grams of lead(II) nitrate, Pb(NO₃)₂, in 100 grams of water has a temperature of 30ºC.
<em>∴ The grams of the salt are undissolved, on the bottom of the beaker are </em><em>(14 g).</em>
