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DaniilM [7]
3 years ago
13

How many formula units are contained in 2.35mol of Iron (III) Oxide

Chemistry
1 answer:
konstantin123 [22]3 years ago
7 0
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.

Answer is 1.42x10^24

You might be interested in
Convert from 1.56×1030 particles of sodium chloride (NaCl) to grams of sodium chloride.
Anika [276]

Answer:

15.14×10⁷ g

Explanation:

Given data:

Number of particles of NaCl = 1.56×10³⁰ particles

Mass of sodium chloride = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ particles

1.56×10³⁰ particles × 1 mol / 6.022 × 10²³ particles

0.259 ×10⁷ mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.259 ×10⁷ mol × 58.44 g/mol

Mass = 15.14×10⁷ g

8 0
3 years ago
What is Atomic mass
larisa86 [58]
The answer is B. Your welcome.
6 0
4 years ago
Read 2 more answers
Question 2<br> How many significant figures does the number have?<br> 23.0702
Pavlova-9 [17]
The number 23.0702 has 6 significant figures.

To answer this, you must have the rules for significant figures,

1. All non-zero numbers ARE significant
2. Zeros between two non-zero digits ARE significant
3. Leading zeros are NOT significant
4. Trailing zeros are ONLY significant if the number has a decimal point

The number 23.0702 has 4 non-zero numbers(rule 1), and both zeros are between two non-zero digits(rule 2). Since all 6 figures in the number 23.0702 are significant, the number 23.0702 has 6 significant figures.
7 0
4 years ago
HELP ASAP!!! WILL GIVE BRAINLIEST! THESE FOUR QUESTIONS PLEASE!
Vesna [10]

1. 12.992 L

2. 2.42 moles

3. 275.52 L

4. 567.844 g

<h3>Further explanation</h3>

Given

moles and volume at STP

Required

mass, volume and moles

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

1. 0.58 moles ammonia :

Volume = 0.58 moles x 22.4 L = 12.992 L

2. 77.5 grams of O₂ :

Moles = 77.5 grams x (1 mol/32 grams) = 2.42

3. 12.3 mole of Bromine gas :

Volume = 12.3 mole   x (22.4 L/1 mole) = 275.52 L

4. 4.8 moles iron(II)chloride :

Mass = 4.48 moles x molar mass ( 126,751 g/mol) = 567.844 g

5 0
3 years ago
For a given sample of ch3oh, the enthalpy change during the reaction is 82.3 kj . how many grams of methane gas are produced?
Leno4ka [110]
The equation is as follows;
 2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be;    =  (2×82.3)/252.3
                               = 0.6524 moles
                  which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g


8 0
3 years ago
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