Answer:
The final pressure in the system is 4.153 atm
Explanation:
Given;
volume of Argon, V(Ar) = 3.34 L
pressure of Argon, P(Ar) = 8.95 atm
volume of oxygen, V(O₂) = 8.00 L
pressure of oxygen, P(O₂) = 2.15 atm
According to Boyle's law;
P₁V₁ = P₂V₂
Where;
P₁ is initial pressure of the gases
P₂ is the final pressure of the gases
V₁ is initial volume of the gases
V₂ is the final volume of the gases
We need to determine the final pressure of the gases;
Total volume of the gas mixtures = 3.34 L + 8.00 L = 11.34 L
Final pressure of Argon in the gas mixture = (8.95 atm) x ( 3.34 L / 11.34 L) = 2.636 atm
Final pressure of oxygen in the gas mixture = (2.15 atm) x (8.00 L / 11.34 L) = 1.517 atm
The final pressure in the system = 2.636 atm + 1.517 atm = 4.153 atm
