![\left[\begin{array}{ccc}22&18\end{array}\right]\times\left[\begin{array}{cccc}5&18&32&40\\25&40&38&12\end{array}\right]\\\\=\left[\begin{array}{cccc}22\cdot5+18\cdot25&22\cdot18+18\cdot40&22\cdot32+18\cdot38&22\cdot40+18\cdot12\end{array}\right]\\\\=\left[\begin{array}{cccc}560&1116&1388&1096\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D22%2618%5Cend%7Barray%7D%5Cright%5D%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%2618%2632%2640%5C%5C25%2640%2638%2612%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D22%5Ccdot5%2B18%5Ccdot25%2622%5Ccdot18%2B18%5Ccdot40%2622%5Ccdot32%2B18%5Ccdot38%2622%5Ccdot40%2B18%5Ccdot12%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D560%261116%261388%261096%5Cend%7Barray%7D%5Cright%5D)
second question:
January: 32 · 22 + 38 · 18 = 704 + 684 = 1388
December: 18 · 22 + 40 · 18 = 396 + 720 = 1116
1388 - 1116 = 272
Answer: $272.
The graph is attached.
We first graph the point where his catch reached the surface, (35, 0). Since it travels upward at a constant rate, the graph will be linear. We also need to know where it starts (what depth it is at when he begins reeling it in). We can use the formula d=rt as a template for our function. d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.
To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35)
This will tell us how much distance it traveled in 35 seconds. 0.1(35)=3.5, so the catch started 3.5m under water. It then travels up at 0.1 m per second.
Answer:
B) 0.004
Step-by-step explanation:
0.001
x 4
----------
0.004
Answer:
This question makes no sense but here we go:
Step-by-step explanation:
Assuming the sum must be equal to six:
x+y = 6
Comment if i'm getting the wrong idea, this question makes like no sense to me. Perhaps a grammatical error?