All categories

3 years ago

Help me solve this problem!!PLEASE help I need this answer and I need to know how to solve this by today!!

2 answers:

8 0

Livia has a total budget of $64.00.

Subtract the cost of the socks from the budget.

64 - 50 = 14

Next, divide 14 by 2.20.

14 ÷ 2.20 = 6.36

So, Livia can buy 6 pairs of socks.

I hope that helped! c:

gogolik [260]3 years ago

6 0

She wants to purchase shoes that cost $ 50
she wants to purchase socks that cost 2.20 each......so the expression for this is 2.20s...with s being the number of pairs of socks bought
and she only has $ 64....so she has to spend 64 or less...< = 64

so ur inequality would be :
50 + 2.20s < = 64.....subtract 50 from both sides
2.20s < = 64 - 50
2.20s < = 14...divide both sides by 2.20
s < = 14 / 2.20
s < = 6.36....so she can purchase 6 pairs of socks without going over

You might be interested in

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Reflect C over the y axis

4vir4ik [10]

Answer:

C' (- 3, 2 )

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

C (3, 2 ) → C' (- 3, 2 )

4 0

3 years ago

What is the value of 3x^2 + 5x + 25, when x = 3<br> (3x^2 means 3x squared)

pentagon [3]

I got 67 but I can guarantee it’s right

8 0

3 years ago

What is the equation of the line parallel to 3x+2y= -4 that goes through the point (4,-1)

sertanlavr [38]

Answer:

y = (-3/2)x + 7

Step-by-step explanation:

3x + 2y = -4 (rearrange to slope intercept form y = mx + b)

2y = -3x - 4

y = (-3/2) x - 2

comparing this to the general form of a linear equation : y = mx + b

we see that slope of this line (and every line that is parallel to this line),

m = -3/2

if we sub this back in to the general form, we get:

y = (-3/2)x + b

We are still missing the value of b. To find this, we are given that the point (4,1) lies on the line. We simply substitute this back into the equation and solve for b.

1 = (-3/2)4 + b

1 = -6 + b

b = 7

substituting this back into the equation:

y = (-3/2)x + 7

6 0

3 years ago

Read 2 more answers

Write "x is less than or equal to zero" three different ways.

garik1379 [7]

The expression "x is less than or equal to zero" can be written in several forms; some examples, however, could be:

x ≤ 0
0 ≥ x
(You could substitute any number in place of 3 for the below)
3 - 3 ≥ x

3 0

3 years ago