Ask question

Ask question

All categories

gizmo_the_mogwai [7]

2 years ago

13

What is find the total area

1 answer:

kenny6666 [7]2 years ago

7 0

You have to find the area of a shape.

You might be interested in

Dana ordered 6 pizzas for her party and each pizza is sliced into quarters. She says in order to find out how many slices there

faltersainse [42]

Answer:

d

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to:

$\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56$

3 0

2 years ago

I need help on this question!

Romashka [77]

It would be C because if you plug all the x-values in to the equation, it would get the same y values, which would satisfy the equation.

4 0

2 years ago

I NEED HELP FAST!!!! 15PTS

Vadim26 [7]

3.option a (-8,2)

4.option b (5,4)

7 0

3 years ago

With food prices becoming a great issue in the world; wheat yields are even more important. Some of the highest yielding dry lan

Rzqust [24]

Answer:

Option E) 61.6

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100 bushels per acre

Standard Deviation, σ = 30 bushels per acre

We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X>x) = 0.90

We have to find the value of x such that the probability is 0.90

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 100}{30})=0.90$

$= 1 -P( z \leq \displaystyle\frac{x - 100}{30})=0.90$

$=P( z \leq \displaystyle\frac{x - 100}{30})=0.10$

Calculation the value from standard normal table, we have,

$P(z$

$\displaystyle\frac{x - 100}{30} = -1.282\\x = 61.55 \approx 61.6$

Hence, the yield of 61.6 bushels per acre or more would save the seed.

7 0

2 years ago