Answer:
31st term = 84
Step-by-step explanation:
Given:
204, 200,196,...
Find:
31st term
Computation:
204, 200,196,...
First term a = 204
Difference d = a3 - a2
Difference d = 196 - 200
Difference d = -4
An = a + (n-1)d
A31 = 204 + (31-1)(-4)
A31 = 204 - 120
A31 = 84
Answer
a nd b
Step-by-step explanation:
Given:
The given value is
.
To find:
The multiplicative inverse of
.
Solution:
We know that
is the multiplicative interval of
if
.
Let
be the multiplicative inverse of the given value
. Then,

Divide both sides by
.


Therefore, the multiplicative inverse of
is
. Hence the correct option is A.
First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
1288991/7776
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Hope this helps you