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Drupady [299]
3 years ago
13

A shoe store is selling a pair of shoes for $60 that has been discontinued by 25%. What was the original selling price?

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

$80

Step-by-step explanation:

The shoe is being sold for 75% (100%-25%) of the original price. So in order to calculate the original price, divide the discounted price ($60) by 75%.

60/0.75 = 80

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Help me plzz show work plz​
iren2701 [21]

Answer:

B

Step-by-step explanation:

Use the formula for radius and circle circumference.

d=2r \\ \\ C=2\pi r

Since we know the diameter, if we divide that by 2, we can get the radius.

29.5/2=14.75

Now we can plug that value into the circumference formula to get the circumference.

C=2(14.75)\pi \\ \\ C=29.5\pi \\ \\ C=93

*Since we're rounding to the nearest inch.

7 0
3 years ago
the area of a desktop is represented by x^2 - 49. find the dimensions of the desktop in terms of x. show work please.​
Levart [38]

Answer:

The dimensions of the desktop are (x+7) units by (x-7) units

Step-by-step explanation:

we know that

The difference of squares is equal to

a^2-b^2=(a+b)(a-b)

we have

x^2-49

Remember that

49=7^2

substitute

x^2-7^2

Applying difference of squares

x^2-7^2=(x+7)(x-7)

therefore

The dimensions of the desktop are (x+7) units by (x-7) units

4 0
3 years ago
A firm makes bulldozers (B), cranes (C) and tractors (T) at two locations, New York City (NYC) and Los Angeles (LA). The matrice
iragen [17]

Answer:

The expression is  

.\ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ B \   \ \ \ \ \ C \ \ \ \ \ T\\M = \left \  NYC} \atop {LA}} \right.  \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]

Step-by-step explanation:

From the question we are told that

    The  number of each items made in the month of January[J] is  

   .\ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ B \  \ \ \ \ C \ \ \ \ \ \ T\\J = \left \  NYC} \atop {LA}} \right.  \left[\begin{array}{ccc}{144}&{474 }&{274}\\{598}&{572}&{302}\\\end{array}\right]

The  number of each items made in the month of February[F] is  

 .\ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ B \  \ \ \ \ C \ \ \ \ \ \ T\\J = \left \  NYC} \atop {LA}} \right.  \left[\begin{array}{ccc}{ 424}&{492}&{546}\\{596 }&{530}&{164}\\\end{array}\right]

Generally given that the production for March of all products at all locations was the average of the January and February production then the number of each items made in the month of March[M] is

    .\ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ B \  \ \ \ \ \ \ \ \ \ \ \ \ C \ \ \ \ \ \ \ \ \ \ \ T\\M = \left \  NYC} \atop {LA}} \right.  \left[\begin{array}{ccc}{\frac{144 +424}{2}}&{\frac{474 +492}{2}}&{\frac{274 +546}{2}}\\{\frac{598 +596}{2}}&{\frac{572 +530}{2}}&{\frac{302+164}{2}}\\\end{array}\right]

=> .\ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ B \   \ \ \ \ \ C \ \ \ \ \ T\\M = \left \  NYC} \atop {LA}} \right.  \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]

5 0
3 years ago
A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he
Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

h(t) = -16t^2 + 30t

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

f(x) = ax^2 + bx + c:

f(\frac{-b}{2a}) = maximum/minimum

i.e we first solve for \frac{-b}{2a}

Then substitute \frac{-b}{2a} for x in f(x) = ax^2 + bx + c

In our case:

First we need to solve \frac{-b}{2a}

Then substitute \frac{-b}{2a} for t in h(t) = -16t^2 + 30t

By comparison:

b = 30

c = -16

\frac{-b}{2a} = \frac{-30}{2 * -16}

\frac{-b}{2a} = \frac{-30}{-32}

\frac{-b}{2a} = \frac{30}{32}

\frac{-b}{2a} = \frac{15}{16}

Substitute \frac{15}{16} for t in h(t) = -16t^2 + 30t

h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})

h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}

h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}

h(\frac{15}{16}) = \frac{-225 + 450}{16}

h(\frac{15}{16}) = \frac{225}{16}

h(\frac{15}{16}) = 14.0625

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because 14.0625 < 15

8 0
3 years ago
There are two cheesecakes in the fridge. The first cheesecake was cut into 10 slices and 4 slices were sold. How much cake is le
olga2289 [7]

Answer: 1³/₅ of cake left

Step-by-step explanation:

There were two cheesecakes.

One was taken and cut into 10 slices, 4 of which were sold. The remainder of Cake A is:

= 10 - 4

= 6 slices

1 cake and 6 slices are therefore left.

As the 6 slices were originally 10, this expression in fraction is:

= 6/10

= 3/5

There are therefore:

= 1³/₅ of cake left

5 0
3 years ago
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