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3 years ago

Someone help please i am so bad at point slope stuff

1 answer:

3 0

1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x

2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1).
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69

3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line.

4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2

5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2

6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4) / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7

7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11

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Given: ABCD is a parallelogram and AC bisects BD. Prove: AB is congruent to BC.

earnstyle [38]

Let's see

In ∆ABE and ∆CBE

BE=BE(Common side)
AE=EC[Diagonals of a parallelogram bisect each other]
<AEB=<BEC[90°]

So by

SAS congruence the triangles are congruent

AB=BC

Proved

Fact:-

It's already given AC is perpendicular to BD

It means diagonals are perpendicular to each other

According to general property of rhombus this parallelogram is also a rhombus.

So sides are equal hence AB =BC

3 0

1 year ago

Help please help!! my grade is down

lisov135 [29]

plug in -2 for x

7*-2 -10 = -24

7 0

3 years ago

PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the

drek231 [11]

Answer:

1) The height of the ball from 0 to 5 seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0

3 years ago

THe temperature is negative 7 degrees and overnight it gets 12 degrees warmer? Then during the day it gets 12 degrees warmer?

Vinil7 [7]

At the start the temperature is -7 overnight it gets 12 degrees warmer so -7+12 =5 degrees than during the day it gets 12 degrees warmer so 5+12= 17 degrees

6 0

3 years ago

What is the value of x? Enter your answer in the box. x =

galina1969 [7]

The answer is: " 11 " .
____________________________________________________
→ " x = 11 " .
____________________________________________________
Explanation:
____________________________________________________
Set up the ratio/ proportion as a fraction:

6 cm / 48 cm = 5 cm / (3x + 7) ;

→ The "cm" units cancel out; since: "cm/cm = 1 " ;

→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;

→ Rewrite as: $\frac{1}{8} = \frac{5}{3x + 7}$ ;

Now, we can "cross-multiply" :
__________________________________________________

Note: $Given: \frac{a}{b} = \frac{c}{d}$ ; $ad = bc$ ;
{b $\neq 0$ ; d $\neq 0$ } .
__________________________________________________

As such:

1 * (3x + 7) = 8 * 5 ;

→ 3x + 7 = 40 ;

Subtract "7" from each side of the equation:

→ 3x + 7 − 7 = 40 − 7 ;

to get:

→ 3x = 33 ;

Now, divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;

→ 3x / 3 = 33 / 3 ;

to get:
____________________________________________________

→ " x = 11 " .
____________________________________________________
→ The answer is: " 11 " .
____________________________________________________

4 0

2 years ago

Read 2 more answers