Answer:
<h2>The empty inside the box is 12,870 cubic centimeters, approximately.</h2>
Step-by-step explanation:
Givens
- The diameter of the globe (sphere) is 30 centimeters,
- The box must has dimensions 30x30.
We need to find each volume to subtract them.


The difference betweem the box and the sphere is

Therefore, the empty inside the box is 12,870 cubic centimeters, approximately.
Answer:
=
+
+
Step-by-step explanation:
=multiple ways to climb a tower
When n = 1,
tower= 1 cm
= 1
When n = 2,
tower =2 cm
= 2
When n = 3,
tower = 3 cm
it can be build if we use three 1 cm blocks
= 3
When n = 4,
tower= 4 cm
it can be build if we use four 1 cm blocks
= 6
When n > 5
tower height > 4 cm
so we can use 1 cm, 2 cm and 4 cm blocks
so in that case if our last move is 1 cm block then
will be
n —1 cm
if our last move is 2 cm block then
will be
n —2 cm
if our last move is 4 cm block then
will be
n —4 cm
=
+
+
Multiply the number in the tens place of the bottom
number by the number in ones place of the top number. So
multiply the 1 by the 5, which makes 5. Multiply the number in
the tens place of the bottom number by the number in tens
place of the top number. Multiply 1 by 2, which equals 2.
Answer:
Less close to one
Step-by-step explanation:
0.006/6,000= 0,000001
I believe the answer is A.