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2 years ago

When water molecules are moving slow enough they?

1 answer:

3 0

The water molecules now are moving slow enough that when they get close to one another, their mutual electrical attraction is able to hold them together.

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Valentin [98]

A) deposition is the processes where particles of rock or laid down in sections with heavier sediments building up first

5 0

2 years ago

Read 2 more answers

How many atoms are in 85.1 grams of neon

strojnjashka [21]

Convert the mass to moles .

85.1 g ÷ 20.18 g/mol = 4.21704658

convert the moles to molecules

4.2170 mol × 6.022^23 molecules/mol = 2.539^24

7 0

2 years ago

Which of the following chemical symbols represents the element silver?

notsponge [240]

Silver is Ag from the latin Argentum

Lead is Pb from the latin Plumbum

8 0

2 years ago

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Calculate the hight of a column of liquid glycerol in meters required to exert the same pressure as 3.02 m if CCl4?

katovenus [111]

Answer:

Approximately $3.81\; \rm m$ .

Explanation:

Look up the density $\rho$ of carbon tetrachloride, $\rm CCl_4$ , and glycerol:

Density of carbon tetrachloride: approximately $1.59\times 10^{3}\; \rm kg \cdot m^{-3}$ .
Density of glycerol: approximately $1.26\times 10^{3}\; \rm kg \cdot m^{-3}$ .

Let $g$ denote the gravitational field strength. (Typically $g \approx 9.81\; \rm N \cdot kg^{-1}$ near the surface of the earth.) For a column of liquid with a height of $h$ , if the density of the liquid is $\rho$ , the pressure at the bottom of the column would be:

$P = \rho\cdot g \cdot h$ .

The pressure at the bottom of this carbon tetrachloride column would be:

$\begin{aligned} P &= \rho \cdot g \cdot h \\ & \approx 1.59\times 10^{3} \; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1} \times 3.02 \; \rm m \approx 4.71 \times 10^{4} \; \rm N \cdot m^{-2} \end{aligned}$ .

Rearrange the equation $P = \rho\cdot g \cdot h$ for $h$ :

$\displaystyle h = \frac{P}{\rho \cdot g}$ .

Apply this equation to calculate the height of the liquid glycerol column:

$\begin{aligned}h &= \frac{P}{\rho \cdot g} \\ &\approx \frac{4.71 \times 10^{4}\; \rm N \cdot m^{-2}}{1.26 \times 10^{3}\; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1}} \approx 3.81\; \rm m\end{aligned}$ .

4 0

2 years ago

Which of the following acids do NOT ionize completely in solution? Check all that apply.

KIM [24]

<span>The following acids do NOT ionize completely in solution because they are not strong acids are as follows:
a HBr
b HI
c H2SO3
d H3N
e HNO2
f HF
</span>

5 0

3 years ago