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2 years ago

How many milliliters of 1.50 M magnesium sulfate soulution is required to supply 2.50 mole of this salt?

Chemistry

1 answer:

arsen [322]2 years ago

3 0

Answer:

1670 ml

Explanation:

molarity x Volume (Liters) = moles => Volume (Liters) = moles/Molarity

Volume needed = 2.50mol/1.50M = 1.67 Liters = 1670 ml.

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3 years ago

If you have 250 mL of 0.75 M LINO2.<br> How many grams of this substance<br> would you have?

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<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

$\boxed{\bold{n=V\times M}}$

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$\tt n=0.25\times 0.75=0.1875$

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2 years ago

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How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

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