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Semmy [17]
3 years ago
15

How many milliliters of 1.50 M magnesium sulfate soulution is required to supply 2.50 mole of this salt?

Chemistry
1 answer:
arsen [322]3 years ago
3 0

Answer:

1670 ml

Explanation:

molarity x Volume (Liters) = moles => Volume (Liters) = moles/Molarity

Volume needed = 2.50mol/1.50M = 1.67 Liters = 1670 ml.

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CaSO4 + AlBr3 > CaBr2 +Al2(SO4)3 What will the coefficient of CaBr2 when the equation is balanced using the smallest possible
Deffense [45]

Answer:

3 will be the correct coefficient of CaBr2

Explanation:

In balancing a chemical equation, numbers should be assigned to both reactants and products as a numerical coefficients until all atoms of elements in both sides of the equation count equal.

The balanced equation of the reaction will be:

3CaSO4 + 2AlBr3 ==> 3CaBr2 + Al2(SO4)3

Looking at the unbalanced equation in the question, in the product Al2(SO4)3 there are 3 SO4 group. This will warrant putting 3 behind CaSO4 in order to balance the atoms of SO4 group. That operation will automatically put the number of Ca atoms in CaSO4 to be 3 therefore making CaBr2 to have 3 coefficient as in the balanced equation. This is to balance the number of Ca atoms in both sides to be 3.

8 0
3 years ago
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Order the bowls from coolest to warmest
vampirchik [111]

Answer:

bowl 5, bowl 3, bowl 4, bowl 1, bowl 2

Explanation:

3 0
3 years ago
Is acetone soluble in water or hexane​
GaryK [48]

Answer:

a

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6 0
3 years ago
The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea
Mariana [72]

Answer:

\frac{1}{8}  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}  

We can construct a table.

<u>No of half-lives</u>  <u>Fraction remaining</u>

            1                       \frac{1}{2}  

            2                      \frac{1}{4}  

            3                      \frac{1}{8}  

The general formula is

\text{Fraction remaining} = \frac{1}{2^{n}}

where <em>n</em> = the number of half-lives.

Thus, \frac{1}{8} of the original carbon remains after 17 190 y.

8 0
3 years ago
Which of the following is an example of ionic compound?
spayn [35]

What you are looking for is something from the left side of the periodic table (the metals), combined with something from the right side of the periodic table.

SiCl4 is something from the middle with something on the right. Not the answer.

HCl is a possible answer, but it is not the best one, because Hydrogen can be on both sides. It is not quite as willing to give up its electrons as the answer.

CCl4 has the same problem as A.

The answer is C

Ca is in column 2 just about as far left as you can get.

Cl is in column 17 which is just about as far right as you can get.

5 0
2 years ago
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