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Semmy [17]
3 years ago
15

How many milliliters of 1.50 M magnesium sulfate soulution is required to supply 2.50 mole of this salt?

Chemistry
1 answer:
arsen [322]3 years ago
3 0

Answer:

1670 ml

Explanation:

molarity x Volume (Liters) = moles => Volume (Liters) = moles/Molarity

Volume needed = 2.50mol/1.50M = 1.67 Liters = 1670 ml.

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look in your science book

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When aqueous solutions of potassium carbonate and cobalt(II) sulfate are combined, solid cobalt(II) carbonate and a solution of
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K2CO3 (aq) + CoSO4 (aq) ---> CoCO3 (s) + K2SO4 (aq)
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Calculate the energy released when 24.8 g Na2O reacts in the following reaction
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Answer:

hey you wanna get it right try this one: 48.0 kcal

was released... at constant pressure.

Explanation:

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3 years ago
"in which direction does this reaction tend to proceed under standard conditions?"
Black_prince [1.1K]

Answer : Right

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6 0
3 years ago
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What volume is needed to make a 2.45 M solution of KCl using 0.50 mol of KCl
Ivan

Answer:

Explanation:

91.4

grams

Explanation:

C

=

m

o

l

v

o

l

u

m

e

2.45

M

=

m

o

l

0.5

L

2.45

M

⋅

0.5

L

=

m

o

l

m

o

l

=

1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225

m

o

l

⋅

(

39.1

+

35.5

)

g

m

o

l

1.225

m

o

l

⋅

74.6

g

m

o

l

=

1.225

⋅

74.6

g

=

91.4

g

4 0
3 years ago
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