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r-ruslan [8.4K]
2 years ago
15

Warm air rising at the equator and cold air sinking at the poles is an example of…

Chemistry
1 answer:
Yanka [14]2 years ago
4 0

Answer:

atmospheric circulation

Explanation:

Atmospheric circulation occurs  because the Sun heats the Earth more at the equator than at the poles.

Warm air is known to rise at the tropics which lies closer to the equator and moves towards the poles. Atmospheric circulation is driven by the rotation of the earth.

The air cools and flows back towards the Equator to be warmed up again. A sort of convection current is thereby set up.

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WILL GIVE BRAINLIEST ANSWER ASAP!!
Margarita [4]

Morphology

Explanation:

The shape and pigment of the hairs are the morphological elements of the two hair strands.

Morphology deals with the study of the form and structure of organisms, plants and their components.

  • The shape, size, color, textures, orientation are all morphological elements that can be used to draw biological comparison between things.
  • It also entails the relationship between the structures with each other.
  • Morphology is an expression of the genotypic make up of an organism.

Learn more:

Traits     brainly.com/question/2908634

#learnwithBrainly

4 0
2 years ago
Pressure is the force exerted by a substance on its container. Of the three phases of matter which one would exert the highest p
Luden [163]

Answer:

Gaseous phase exert more pressure on container.

Explanation:

Pressure:

It is the force exerted by the substance on its container.

Mathematical expression:

P = F/A

P = pressure

F = force

A = area

We know that there are phases of matter solid liquid and gas.

Gases don't have definite volume and shape and take the shape and volume of container in which it present.  Molecule of gases randomly move everywhere and occupy all available space.  The molecules of gas randomly move collide with each other and also the wall of container their kinetic energy also increased because of this collision and pressure is produced

While in case of liquid molecules are packed and they can not move freely thus did not exert pressure like gaseous molecules.

In case of solids molecules are tightly packed and form more compact structure. They can not move thus did not exert pressure to the wall of container.

Properties of gases:

Molecule of gases randomly move everywhere and occupy all available space.

Gases don't have definite volume and shape and take the shape and volume of container in which it present.

Their densities are very low as compared to the liquid and solids.

Gas molecules are at long distance from each other therefore by applying pressure gases can be compressed.

The very weak inter molecular forces are present between gas molecules.

Properties of Liquid:

Liquid have definite volume but don,t have definite shape.

Their densities are high as compared to the gases but low as compared to the solids.

In liquid, molecules are close to each other and have greater inter molecular forces as compared to the gas molecules.

Properties of solids:

Solids have definite volume and shape.

In solids molecules are tightly pack and very close to each other.

Their melting and boiling point are every high.

The densities of solids are also very high as compared to the liquid and gas.

There are very strong inter molecular forces are present between solid molecules.

6 0
3 years ago
how much heat is released when 70.9g of water at 66C cools to 25C? The specific heat of water is 1 cal/gC
Serga [27]

Answer:

-12162.47 joules (or -12000 joules when accounting for significant figures)

Explanation (btw I used 1 cal as 4.184 joules because SI units are better):

q = m c delta T

q = (70.9) (4.184) (25 - 66)  

q = (70.9) (4.184) (-41)

q = -12162.47 joules

7 0
3 years ago
What is 2.75 mol of O2
ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

3 0
2 years ago
There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
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