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r-ruslan [8.4K]
3 years ago
15

Warm air rising at the equator and cold air sinking at the poles is an example of…

Chemistry
1 answer:
Yanka [14]3 years ago
4 0

Answer:

atmospheric circulation

Explanation:

Atmospheric circulation occurs  because the Sun heats the Earth more at the equator than at the poles.

Warm air is known to rise at the tropics which lies closer to the equator and moves towards the poles. Atmospheric circulation is driven by the rotation of the earth.

The air cools and flows back towards the Equator to be warmed up again. A sort of convection current is thereby set up.

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What is the amount of heat energy absorbed when 36 grams of ice at -20oC is melted to water at 0oC?
Ulleksa [173]

Answer:

Q = 1461.6 J

Explanation:

Given data:

Mass of ice = 36 g

Initial temperature = -20°C

Final temperature = 0°C

Amount of heat absorbed = ?

Solution:

specific heat capacity of ice is 2.03 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  0°C - (-20°C)

ΔT = 20°C

Q = 36 g ×2.03 j/g.°C×20°C

Q = 1461.6 J

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3 years ago
Calculate the mean rate of reaction when 23 cm<br> of gas<br> is produced in 15 seconds.
katrin2010 [14]

Answer:

1.53 cm/s

Explanation:

Rate = Length/time

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        = 1.53 cm/s

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2 years ago
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If a wave has a frequency of 2.85x10^10 its wavelength is ?
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4 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
3 years ago
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