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r-ruslan [8.4K]
2 years ago
15

Warm air rising at the equator and cold air sinking at the poles is an example of…

Chemistry
1 answer:
Yanka [14]2 years ago
4 0

Answer:

atmospheric circulation

Explanation:

Atmospheric circulation occurs  because the Sun heats the Earth more at the equator than at the poles.

Warm air is known to rise at the tropics which lies closer to the equator and moves towards the poles. Atmospheric circulation is driven by the rotation of the earth.

The air cools and flows back towards the Equator to be warmed up again. A sort of convection current is thereby set up.

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8 0
2 years ago
Consider these diagrams representing particle arrangements. Which correctly matches the diagrams with the three phases of matter
hram777 [196]

the answer is c) just took the test so these are facts.

4 0
3 years ago
How high the boiling point can be elevated depends on the
n200080 [17]
<span>C) Density of the particles of solute in the solution</span>
7 0
2 years ago
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A 100-mL graduated cylinder w
kicyunya [14]

Answer:

h=100.8cm

Explanation:

Hello,

In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\  \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\

Now, the total volume is:

V=50.6mL+34mL=84.6mL

Which is equal to:

V=84.6cm^3

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm

Best regards.

3 0
3 years ago
What are the major organic products are formed when the following compounds react with methylmagnesium bromide (CH3MgBr), follow
Sliva [168]

Answer:

Major organic products are- (a) propan-1-ol and (b) 2-methylpropan-2-ol

Explanation:

methyl magnesium bromide gives nucleophilic addition reaction with carbonyl group. Because methyl magnesium bromide is a strong nucleophile and carbonyl group is a strong electrophilic center.

Propanal contains an aldehyde group and propanone contains a ketone group. hence they both give nucleophilic addition with methyl magnesium bromide.

Dilute acid is added to protonate the alkoxide produced during nucleophilic addition.

Reactions are shown below.

6 0
2 years ago
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