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gogolik [260]
2 years ago
12

Let A and B be two events. The probability that event B occurs is 0.72. The probability that events B and A both occur is 0.24.

Mathematics
2 answers:
Sedaia [141]2 years ago
6 0
C is the answer to this question. I hope this helps.
myrzilka [38]2 years ago
6 0

Answer:C

Step-by-step explanation:

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Find the values of x,y,z. This diagram is not a scale.
Serjik [45]

Important:
                             The sum of the three angles inside
                              every triangle is always 180°.


First, look at the left triangle alone.
Two of its angles are 46° and 58° .  (46° + 58° ) = 104°
That leaves (180° - 104° ) = 76° degrees for the third angle.
The third angle in that triangle is 'x'. 
                                                         x = 76° .

At the point where 'x' and 'z' come together:
'x' and 'z' are a "linear pair".
Placed side-by-side, they form a straight line.
So (x + z) = 180° .
But  x = 76°.
So z = (180° - 76°).              z = 104° .

Now look at the the skinny triangle on the right alone.
The angle at the top is 13°, and  z = 104°. 
(13° + 104°) = 117° . 
That leaves (180° - 117°) = 63° for the third angle.
'y' is the third angle.
                                                 y = 63° .

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2 years ago
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What's the appropriate domain<br>please help ​
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100 x 100 uygjfdis9iiugjnjjbjf
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An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl
Zanzabum

Answer:

about 32%

Step-by-step explanation:

8 0
3 years ago
Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

3 0
3 years ago
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