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kondaur [170]
3 years ago
5

12x─ 15 = 6 ─ 3x answered as a fraction

Mathematics
2 answers:
KiRa [710]3 years ago
8 0

Answer:

x is equal to one and two fifths.

Step-by-step explanation:

Given:

12x - 15 = 6 - 3x

Let's start by noticing that every term in that equation is divisible by 3.  That means we can factor 3 out of it, giving us:

4x - 5 = 2 - x

Now we'll add x to both sides:

4x + x - 5 = 2 - x + x

5x - 5 = 2

An then we add 5 to both sides:

5x - 5 + 5 = 2 + 5

5x = 7

Finally, we can divide both sides by 5 to get the final answer:

5x ÷ 5 = 7 ÷ 5

x = 7/5

To put that in proper form it would be:

x = 1 \frac{2}{5}

telo118 [61]3 years ago
5 0

Answer:

x=1.4 or 21/15

Step-by-step explanation:

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SOLVE. integration of (1-v) /(1+v^2)
Marta_Voda [28]
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:

y= 1+v^2
 so
 dy= 2v
 and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
 (1/2) (In y)finally you plug in the initial variables:

(1/2)(In [1+v^2])

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ArcTan (y) + (1/2)(In [1+v^2])
6 0
3 years ago
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The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
Solution to 3x+2y=24
seropon [69]

Answer:

it’s a multi step equation

Step-by-step explanation:

solve like a multi step

7 0
3 years ago
Ac is tangent to circle o at point c what is the length of ac?
MissTica

Answer:

The Answer is 12

Step-by-step explanation:

Use Pythagorean theorem. AB=8 and BO=5 We still need to find AO

AO=AB+BO

8+5

AO=13

Now solve for AC

AC^2 + OC^2= AO^2

AC^2+5^2=13^2

AC^2+ 25=169

AC^2=144

AC= 12

5 0
3 years ago
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