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Ratling [72]
3 years ago
15

How to balance 4NaNO3 + 5PbO → 8Pb(NO3)2 + 7Na2O with coefficients?

Chemistry
1 answer:
Marysya12 [62]3 years ago
6 0

The balanced equation

2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O

<h3>Further explanation</h3>

Given

Reaction

NaNO3 + PbO → Pb(NO3)2 + Na2O

Required

Balanced equation

Solution

  • 1. Give coefficient

aNaNO₃ + bPbO → Pb(NO₃)₂ + cNa₂O(Pb(NO₃)₂ ⇒coefficient 1 for the most complex compounds)

  • 2. Make an equation

N, left=a, right=2⇒a=2

Na, left = a, right=2c⇒a=2c⇒2=2c⇒c=1

Pb, left = b, right=1⇒b=1

The equation becomes :

2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O

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10.What is the mass number of silicon (Si) when it has 15 neutrons?Required to answer. Single line text.
fgiga [73]

Answer:

29

Explanation:

no of electrons=14

neutron no=15

14+15

29

3 0
3 years ago
What is Δn for the following equation in relating Kc to Kp?CH4(g) + H2O(g) ↔ CO(g) + 3 H2(g)-120-3-2
Sindrei [870]

Answer: Δn for the following equation in relating Kc to Kp is 2.

Explanation:

The balanced chemical equation is:

CH_4(g)+H_2O(g)\rightleftharpoons CO(g)+3H_2(g)

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

Where,

K_p = equilibrium constant in terms of partial pressure

K_c = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=4-2=2

Putting values in above equation, we get:

K_p=K_c\times (RT)^{2}

Thus the value of Δn for the following equation in relating Kc to Kp is 2.

5 0
3 years ago
Sam noticed on a climate map that most of the areas with high rainfall and a tropical climate were located in one region. Why ar
denis23 [38]

Answer:

Okay here's the answer ↓

Step-by-step explanation:

Tropical climate is one of the five major climate groups in the Köppen climate classification. Tropical climates are characterized by monthly average temperatures of 18 ℃ (64.4 ℉) or higher year-round and feature hot temperatures. Annual precipitation is often abundant in tropical climates, and shows a seasonal rhythm to varying degrees. There are normally only two seasons in tropical climates, a wet season and a dry season. The annual temperature range in tropical climates is normally very small. Sunlight is intense because they are receiving direct sunlight.

5 0
3 years ago
Một đơn vị cacbon có khối lượng bằng 0.16605.10²³(g) khối lượng tính bằng gam của nguyên tử Kali (K=39) là:?
steposvetlana [31]
<h3>sorry I can't understand your saying about.. hahahahahhaha </h3>
7 0
3 years ago
Consider the fermentation reaction of glucose: C6H12O6 → 2C2H5OH + 2CO2 A 1.00-mol sample of C6H12O6 was placed in a vat with 10
inessss [21]

Answer:

% yield = 73.48 %

Explanation:

The fermentation reaction is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂          

The percent yield of C₂H₅OH is given by:

\% yield = \frac{m_{E}}{m_{T}} * 100

<em>where m_{E}: is the obtained mass of C₂H₅OH = 67.7g and m_{T}: is the theoretical mass of C₂H₅OH.     </em>

The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:  

m_{T} = mol * M

<em>where M: is the molar mass of C₂H₅OH =  46.068 g/mol</em>

m_{T} = 2 moles * 46.068 g/mol = 92.136 g                

Hence, the percent yield of C₂H₅OH is:

\% yield = \frac{67.7 g}{92.136 g}*100 = 73.48 \%

I hope it helps you!                  

3 0
3 years ago
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