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Ratling [72]
3 years ago
15

How to balance 4NaNO3 + 5PbO → 8Pb(NO3)2 + 7Na2O with coefficients?

Chemistry
1 answer:
Marysya12 [62]3 years ago
6 0

The balanced equation

2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O

<h3>Further explanation</h3>

Given

Reaction

NaNO3 + PbO → Pb(NO3)2 + Na2O

Required

Balanced equation

Solution

  • 1. Give coefficient

aNaNO₃ + bPbO → Pb(NO₃)₂ + cNa₂O(Pb(NO₃)₂ ⇒coefficient 1 for the most complex compounds)

  • 2. Make an equation

N, left=a, right=2⇒a=2

Na, left = a, right=2c⇒a=2c⇒2=2c⇒c=1

Pb, left = b, right=1⇒b=1

The equation becomes :

2NaNO₃ + PbO → Pb(NO₃)₂ + Na₂O

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Answer: 1.25 grams of Potassium-40

Explanation: When the amount of a compound is consumed by half, the time passed is called "the half life". This term is particularly important in nuclear chemistry. Potassium-40 is an isotope of potassium element and it is radioactive. As a result, the consumption time of this radioactive isotope is valuable information since radioactive isotopes are detrimental to health and nature.

For example, in this question, within 1.3 billion years, half amount of the potassium-40 disappears. 2.6 billion years ago, there were 5 grams of potassium-40 and when 1.3 billion years pass, half of the 5 grams of potassium-40 will disappear and there will will be 2.5 grams of potassium-40 left (5 grams of potassium-5 grams of potassium*(1/2)[half amount]=2.5 grams of potassium-40 left). As a result, 2.5 grams of potassium-40 is the amount that is present 1.3 billion years ago (2.6 billion years-1.3 billion years [half-life]=1.3 billion years). There will be 1.3 billion years left until today, so we still have to calculate the amount disappeared in 1.3 billion years. Thus, half of the 2.5 grams must disappear in 1.3 billion years left (2.5 grams - 2.5 grams*(1/2)[half amount]=1.25 grams). Finally, we have 1.25 grams of potassium-40 left since 2.6 billion years ago.

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mark me as brainliest if it helped you

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Due to the lack of information provided, the best I can give you is this:

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