2. The combustion of heptane (C7H16) in oxygen spontaneously occurs. The products of the reaction are carbon dioxide and water v
1 answer:
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Here is the full question:
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes? (Round your answer to three decimal places.
Answer:
0.046 %
Explanation:
The rate-in;
= 0.8
The rate-out
=
=
We can say that:
where;
A(0)= 0.2% × 6000
A(0)= 0.002 × 6000
A(0)= 12
Integration of the above linear equation =
so we have:
∴
Since A(0) = 12
Then;
Hence;
∴ the concentration at 10 minutes is ;
= %
= 0.0456667 %
= 0.046% to three decimal places
Answer:
Approximately .
Explanation:
Make use of the molar mass data () to calculate the number of moles of molecules in that
of
:
.
Make sure that the equation for this reaction is balanced.
Coefficient of in this equation:
.
Coefficient of in this equation:
.
In other words, for every two moles of that this reaction consumes, two moles of
would be produced.
Equivalently, for every mole of that this reaction consumes, one mole of
would be produced.
Hence the ratio: .
Apply this ratio to find the number of moles of that this reaction would have produced:
.