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3 years ago

What methods of heat transfer will occur in your solar oven?

Chemistry

1 answer:

Arlecino [84]3 years ago

6 0

Answer: Convection, Conduction, and radiation

***If you found my answer helpful, please give me the brainliest. :) ****

You might be interested in

Calculate the number of formula units in 1.87 mol of NH4Cl

nydimaria [60]

Answer:

1.13 x 10²⁴formula units

Explanation:

Given parameters:

Number of moles of NH₄Cl = 1.87mol

Unknown:

Number of formula units = ?

Solution:

From mole concept;

1 mole of a substance contains 6.02 x 10²³ formula units

Now;

1.87 moles of NH₄Cl 1.87 x 6.02 x 10²³ = 1.13 x 10²⁴formula units

4 0

3 years ago

How many grams of copper (II) oxide will react with 10 liters of hydrogen gas?

Svetradugi [14.3K]

Answer:

maybe 200g

I don't know thats just a guess

HOPE ITS TURE

8 0

3 years ago

Why do things dissolve so well in water ?

Goshia [24]

Answer:

Explanation:

Water is called the universal solvent. It is a polar molecule (105 degree angle between the H atoms) that gives it a + and a - side so to speak....which allows it to 'pull apart' substances....overcome their intra-molecular attractions to each other ...i.e. disssovle them

4 0

3 years ago

A block of lead displaces 50.5ml of water. The block weighs 698 g. From this

Natasha2012 [34]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{698}{50.5} \\ = 13.8217...$

We have the final answer as

Hope this helps you

4 0

3 years ago

If a solution containing 45.101 g of mercury(II) acetate is allowed to react completely with a solution containing 12.026 g of s

AnnyKZ [126]

Answer:

14.533 grams of solid precipitate of mercury(II) dichromate will form.

Explanation:

$Hg(CH_3COO)_2(aq)+Na_2Cr_2O_7(aq)\rightarrow HgCr_2O_7(s)+2CH_3COONa(aq)$

Moles of mercury(II) acetate = $\frac{45.101 g}{318.70 g/mol}=0.14152 mol$

Moles of sodium dichromate = $\frac{12.026 g}{261.97 g/mol}=0.045906 mol$

According to reaction , 1 mole of sodium dichromate reacts with 1 mole of mercury(II) acetate , then 0.045906 moles of sodium dichromate will recat with :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) acetate

This means that mercury(II) acetate is present in an excess amount and sodium dichromate is present in limiting amount.So, amount of precipitate will depend upon moles of sodium dichromate.

According to reaction , 1 mole of sodium dichromate gives 1 mole of mercury(II) dichromate , then 0.045906 moles of sodium dichromate will give :

$\frac{1}{1}\times 0.045906 mol=0.045906 mol$ of mercury(II) dichromate

Mass of 0.045906 moles of mercury(II) dichromate:

0.045906 mol × 316.59 g/mol = 14.533 g

14.533 grams of solid precipitate of mercury(II) dichromate will form.

3 0

4 years ago