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nignag [31]
3 years ago
9

What is Δn for the following equation in relating Kc to Kp?CH4(g) + H2O(g) ↔ CO(g) + 3 H2(g)-120-3-2

Chemistry
1 answer:
Sindrei [870]3 years ago
5 0

Answer: Δn for the following equation in relating Kc to Kp is 2.

Explanation:

The balanced chemical equation is:

CH_4(g)+H_2O(g)\rightleftharpoons CO(g)+3H_2(g)

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

Where,

K_p = equilibrium constant in terms of partial pressure

K_c = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=4-2=2

Putting values in above equation, we get:

K_p=K_c\times (RT)^{2}

Thus the value of Δn for the following equation in relating Kc to Kp is 2.

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Which diagram shows a wave with the highest frequency? Chemistry question.
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The correct answer is D

Explanation:

Wave frequency is mainly determined by the number of waves that pass through a specific point. In a diagram, this can be found by analyzing the number of crests (top of the wave) and the space between them. For example, wave B is the one with the lowest frequency because there is only one crest and this shows only one wave passing at a specific point. On the opposite, wave D is the one with the highest frequency because this shows multiple crests and this indicates the frequency is high or that many waves pass through a specific point in a short time.

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3 years ago
In a solution of H2SO4, rank the concentration of H2SO4, H+, SO42- from highest concentration to lowest concentration.
Softa [21]

Answer:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

Explanation:

H₂SO₄ is a strong acid, which means that most of it ionizes in aqueous solution.

Since it is a diprotic acid (two hydrogen ions) its ionization occurs in two steps:

  • H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

  • HSO₄⁻ (aq) → H⁺(aq) + SO₄²⁻(aq)

Thus, almost all H₂SO₄ has ionized and its final concentration is almost nothing.

After the first ionization, the conentrations of H⁺(aq) and HSO₄⁻ are equal but by the second ionization more H⁺ ions are produced along with SO₄⁻.

You can show it as one step dissociation, assuming 100% dissociation (given this is a strong acid):

By the stequiometry you can build this table:

                 H₂SO₄ (aq) → 2H⁺(aq) + SO₄²⁻(aq)

Initial                A                 0              0

Change           - x               +2x          +x

Equilibrium       A - x           2x             x

As explained, A - x is very low, and 2x is twice x. Thus,

The rank of the concentrations from highest to lowest is:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

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How to say the first 20 elements easily​
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Try saying these over again and practicing for at least an hour a day!
3 0
3 years ago
Read 2 more answers
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