Radiation is the answer fam..............................
Answer:
Explanation:
Q = Ce . m .ΔT
Q : calor
Ce : calor especifico
m: masa
ΔT : variación de temperatura
capacidad térmica : 0,550 cal / °C
lectura :
por 1 °C se tiene 0,550 cal
por lo tanto tenemos datos de la temperatura y del calor
pero no olvidar las unidades en el sistema internacional :
Ce : J / kg . K
J: joules
kg: kilogramo
K: kelvin
pasar de gramos a kilogramos
pasar de calorías a joules
pasar de grado celsius a kelvin
1000g equivale a 1kg
15g equivale a 0,015 kg
K= °C + 273 ⇒ formula para pasar de grado celsius a kelvin
K= 1 + 273
K= 274
1 caloría equivale a 4,184 joules
0,550 caloría equivale a 2,3012 joules
ahora como todos los datos ya están en el S.I remplazamos en la formula
Q = Ce . m .ΔT
2,3012 = Ce . 0,015.274
Ce=0,5599 J / kg. K
Since it's C2, then it must be two Carbon atoms. Think of it this way; there are two atoms of Hydrogen in a water molecule, so we now have H2O.
The half-life of the reaction is 101.9 min
<h3>First order reaction </h3>
When a reaction's pace and reactant concentration are inversely correlated, the process is known as a first-order reaction. To put it another way, the reaction rate doubles when the concentration does. One or two reactants can be present in a first-order reaction, as in the case of the decomposition process.
<h3>The half-life of first-order reaction:-</h3>
The amount of time it takes for the initial concentration of the reactant(s) to decrease by half is known as the half-life of a chemical reaction (abbreviated as "t1/2").
<h3 /><h3>Calculation:-</h3>
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068 per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
Learn more about first order reaction here :-
brainly.com/question/27754430
#SPJ4
Answer:
<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>
Explanation:
An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:
<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>
Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation.
Also, the sum of the superscripts (masses) is the same on each side of the equation.
Now try figuring out Am-241
