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mestny [16]
3 years ago
14

In question 1, Fatima found that 2 crates of 100 boxes can be filled using the 3,258 cookies produced each day. Subtracting 2,40

0 from 3,258 leaves 858 cookies that still need to be packaged.
Fatima now uses base ten blocks and a rectangular array to find how many boxes of 12 can be filled with these 858 cookies.

Based on her calculations shown below, did Fatima perform the calculation correctly? Why or why not? Select ALL reasons that are true.

https://images.freckle.com/curriculum/math/dok/en/5.NBT.6-dok3-1-q2.svg

(The managers want to know how many boxes of 12 cookies can be filled with the 3,258 cookies that have been baked. Fatima starts by subtracting the largest number of boxes she can easily calculate. She knows that 100 boxes of 12 cookies can be put into one crate. How many crates can be filled from the total of 3,258 cookies? i found the answer it is 2 crates)
Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0

Answer:

I think it's correct. :)

I hope it helped.

Alla [95]3 years ago
3 0
I think it’s correct
I hope this help you :)
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miss Akunina [59]

Answer:

JL = 54

Step-by-step explanation:

JL = JK + KL

JK = KL

8x+11 =14x-1

12 = 6x

x = 2

substitute for x:

8(2)+11 + 14(2)-1 = JL

JL = 16+11+28-1

JL = 54

7 0
3 years ago
The difference of the quotient m and 9 and the quotient of n and 30
Zanzabum
Answer: (30m-9n)/270

First we start with m/9-n/30.

We multiply the denominators to get 270.

Then we multiply the numerators by the original denominators to get (30m-9n).

To check, we can use m=2, and n=4

2/9-4/30=4/45

(30*2-9*4)/270=24/270=4/45
5 0
3 years ago
(( NEED HELP ))
sergiy2304 [10]

Answer:

  C)  x/2 +2y = 4

Step-by-step explanation:

Of the equations offered, only equation C has the given point as a possible solution.

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Since the graph is not given, we don't know if the given point is on the graphed equation.

3 0
3 years ago
What is the common denominator of 1 2/3 and 3/4
Arturiano [62]
The common denominator is 12
4 0
3 years ago
At a local fitness​ center, members pay a ​$10 membership fee and ​$5 for each aerobics class. Nonmembers pay ​$6 for each aerob
sveta [45]
One way to solve it is writing two equations based on the info so

y = 5x + 10 for members
y = 6x for nonmembers

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and to find their intersection point (where the values will be the same), you just set them equal to each other:

5x + 10 = 6x

subtract 5x

x = 10 classes
7 0
3 years ago
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