Find the difference of(ab+8a+1)-(-6ab+4)
1 answer:
Hey there!
When finding the difference of expressions like these, there's a few things you should keep in mind.
1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve.
2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them.
3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses.
With all that in mind, you can go ahead and solve for your difference, like so:
will be your difference.
Hope this helped you out! :-)
When finding the difference of expressions like these, there's a few things you should keep in mind.
1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve.
2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them.
3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses.
With all that in mind, you can go ahead and solve for your difference, like so:
Hope this helped you out! :-)
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Answer:
∠EGB and ∠AGF are congruent;
Transitive Property of Equality
Step-by-step explanation:
The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other
Vertical angles are congruent i.e their measures are equal
Look at the attached graph
Given:
AB // CD
E , G , H , F are col-linear
The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD
∵ AB and EF intersected at point G
∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem
When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent ( vertical angle theorem)
∵ AB // CD and EF is a transversal
∴ m∠AGF = m∠CHF (corresponding angles theorem)
Transitive Property of Equality: if one angle is equal to two other angles, then the two other angles are equal
Therefore, If a = b and b = c, then a = c
∵ m∠EGB = m∠AGF
∵ m∠AGF = m∠CHF
∴ m∠EGB = m∠CHF (transitive property theorem)
∠EGB and ∠AGF are congruent; Transitive Property of Equality
Answer:
(-∞, -2), (-2, -0.618), and (1.618, 3)
Step-by-step explanation:
The red arrows indicate the regions in which the function is decreasing.
The corresponding intervals are (-∞, -0.618) and (1.618, 3),
Let's examine the intervals given.
(-∞, -2): Yes, decreasing.
(-2, -0.618): Yes, decreasing.
(-2, 0.689): No. Decreasing in (-2, -0.618) but increasing in (-0.618, 0.689).
(-1.17, 0.689): No. Decreasing in (-1.17, -0.618) but increasing
in (-0.618, 0.689).
(0.698, 71.457): No. Increasing from (0.698, 1.618), decreasing in (1.618, 3) and increasing in (3, 71.457).
(1.618, 3): Yes, decreasing.
(2.481, ∞): No. Decreasing in (2.481, 3) but increasing in (3, ∞).
The three choices that indicate a decreasing interval are (-∞, -2),
(-2, -0.618), and (1.618, 3).
