Answer:
Option B is the correct answer.
Explanation:
- In the above code, the loop will execute only one time because the loop condition is false and it is the Do-While loop and the property of the Do-while loop is to execute on a single time if the loop condition is false.
- Then the statement "x*=20;" will execute one and gives the result 200 for x variable because this statement means "x=x*20".
- SO the 200 is the answer for the X variable which is described above and it is stated from option B. Hence it is the correct option while the other is not because--
- Option A states that the value is 10 but the value is 200.
- Option C states that this is an infinite loop but the loop is executed one time.
- Option D states that the loop will not be executed but the loop is executed one time
I might be true and might not which chances are 50%
B.using too much jargon means you are using words that may be unfamiliar to the audience. <span>is the answer. jargon is</span><span> difficult words that others might not understand.</span>
Answer: False
Explanation: It is sent to committee then senate.
Complete question is attached as snapshot.
Answer:
This will result in a compilation error.
Here's the inheritance hierarchy:
Meg -> Lois -> Brian -> Stewie
Now Meg has 2 public Fxns, a() and toString().
Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.
So finally Lois has fxns a(), b() and toString().
Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.
Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.
In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.
This results in a compilation error.
Explanation:
