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lyudmila [28]
3 years ago
15

Which of the following guidelines about the subject line of e-mail messages is most appropriate?

Computers and Technology
2 answers:
alekssr [168]3 years ago
5 0

Answer: 2: Use the subject line wisely to let your reader know the main purpose of the e-mail.

============================================================

Explanation:

The subject line is like the title of a book. You want to give a quick sense of what the email is about, but you also don't want to put the entire contents of the book in the title. The subject line only has so much room. Even less room is available if the reader is checking their email on their mobile device.

Choice 1 is false because subject lines are important. I can't think of a case where you can omit the subject line entirely (ie leave it blank), unless it's a situation where the recipient knows in advance what the topic is about. Though that may be rare.

Choice 3 is false. Yes you want to keep the subject line short, but you also don't want to be cryptic or confusing. If you can get away with using 1 or 2 words, then go ahead and do so. However, you may need more words to convey the topic of the email. Go with what feels right and try to put yourself in the shoes of the person reading your email. Ask yourself "Does this convey the message I want to send?"

Choice 4 is false. As mentioned, you do not want to put the entire email in the subject line. The exception of this rule is that if the email is really really short. For every other case, you should have a fairly short title and then go over the details in the email main body itself.

Vikki [24]3 years ago
4 0

Answer:

Use the subject line wisely to let your reader know the main purpose of the e-mail.

Explanation:

i got it right on edge 2021

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(Best Buy Part A) At a Best Buy store, the forecast for the annual demand of a Motorola cell phone is 15600. Demand forecasts ar
Nataly_w [17]

Explanation:

a. The computation of the economic order quantity is shown below:

= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}

= \sqrt{\frac{2\times \text{\15,600}\times \text{\$400}}{\text{\$5}}}

= 1,580 units

The carrying cost is

= $50 × 10%

= $5

b. The number of orders would be equal to

= Annual demand ÷ economic order quantity

= 15,600 ÷ 1,580

= 9.87 orders

Ordering cost = Number of orders × setup cost per order

= 9.87 orders × $400

= $3,949.37

c. The average inventory would equal to

= Economic order quantity ÷ 2

= 1,580 units ÷ 2

= 790 units

Carrying cost = average inventory × carrying cost per unit

= 790 units × $5

= $3,950

c. Now the total cost

= Setup cost + carrying cost

= $3,949.37 + $3,950

= $7,899.37

8 0
3 years ago
1. Write a recursive method to determine if a character is in a list of characters in O(logN) time. Mathematically prove (as we
sergeinik [125]

Answer:

1)

public class BinarySearch {

// Returns index of x if it is present in arr[l..

// r], else return -1

int binarySearch(char arr[], int l, int r, char x)

{

if (r >= l) {

int mid = l + (r - l) / 2;

 

// If the element is present at the

// middle itself

if (arr[mid] == x)

return mid;

 

// If element is smaller than mid, then

// it can only be present in left subarray

if (arr[mid] > x)

return binarySearch(arr, l, mid - 1, x);

 

// Else the element can only be present

// in right subarray

return binarySearch(arr, mid + 1, r, x);

}

 

// We reach here when element is not present

// in array

return -1;

}

 

// Driver method to test above

public static void main(String args[])

{

BinarySearch ob = new BinarySearch();

char arr[] = {'a','c','e','f','g','h'};

int n = arr.length;

char x = 'g';

int result = ob.binarySearch(arr, 0, n - 1, x);

if (result == -1)

System.out.println("Character not present");

else

System.out.println("Character found at index " + result);

}

}

2)

import java.io.*;

import java.util.*;

public class Test{

public static boolean checksame(String s)

{

 

Stack<Integer> stack= new Stack<Integer>();

for(int i=0;i<s.length();i++)

{

if(s.charAt(i)=='0')

{

if(stack.empty()==false)

{

if((Integer)stack.peek()==1)

stack.pop();

else

stack.push(0);

}

else

{

stack.push(0);

}

}

else if(s.charAt(i)=='1')

{

if(stack.empty()==false)

{

if((Integer)stack.peek()==0)

stack.pop();

 

else

stack.push(1);

}

else

{

stack.push(1);

}

 

}

}

return stack.empty();

}

public static void main(String []args){

System.out.println(checksame("a0w1220"));

}

}

Explanation:

5 0
3 years ago
How can I call moderator in braily app ???
SVETLANKA909090 [29]

Hi

You can directly message them.

And just in case you don't know how to message in brainly, then:

If you are using app, then

• Go to your profile and go in the option followers/following.

• There you'll see an option to search, slick that and search the name of moderators.

• Do to there profile and you'll see 2 options ( given in image attached) 1, to follow and 2nd to message.

click \: the \: 2nd \: optionclickthe2ndoption

And just in case, you are using website, then:

• Go to their profile and you'll see an option saying " write a message", click that and you'll able to message them.

Just in case you don't know the names of moderators of Brainly ( you are new here)

So here are some of them:

• Siddhartharao77

• Nikki57

• Praneethworldtopper

• Anvigottlieb

• RehanAhmadXLX

• Abhi178

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Hope this helps!!!

Thanks...

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5 0
3 years ago
A=1/2h(a+b) solve for h
devlian [24]

A=1/2h(a+b)

1/2 can be said as 0.5

so

A=0.5h(a+b)

0.5h is being multiplied with (a+b), taking this expression of left hand side gives

A/0.5(a+b)=h

OR

h=A/0.5(a+b)

This is the final answer

8 0
3 years ago
Eugene wants to indent a paragraph, but the ruler is not present. Which tabs could Eugene use in order to accomplish his goal?
Anettt [7]

Answer:

The answer is "View and page layout."

On google docs, you can click 'tab' on the keyboard to indent a paragraph. I don't know if that's the same on all software though.

hope this helps

7 0
3 years ago
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