Answer:
e. All conditions necessary to apply the chi-square test for homogeneity are satisfied here.
Step-by-step explanation:
The chi square statistic can also be used when the rows of the table which look like a contingency table represent each a different sample or set of observations. The hypothesis to be tested is that two or more different random samples come from the same population or that the samples are homogeneous . The χ² test applied in this situation is called test of homogeneity.
The conditions for the chi square test of homogeneity are
1) the sample is a random sample
2) all expected counts are greater or equal to 5.
In the given question the sample selected are random samples and all the expected counts are greater than 5.
Also the 2 samples have been chosen from the same population and tested whether they have the same results or not.
Part e is the best option.
Answer:
<h2>It is 48 cm^3</h2>
Step-by-step explanation:
I hope that is useful for you :)
Bob-Joe-Sam, Sam-Joe-Bob, Bob-Sam-Joe, Sam-Bob-Joe, Joe-Bob-Sam, Joe-Sam-Bob
Hope this helps
For a normal distribution <em>only, </em>for a population, not for particular sample.
proportion between 1 standard deviation, independent of μ and σ , is given by:
P(Z<1)-P(Z<-1)
=0.841345-0.158655=0.682689
=0.68 (to two places of decimal)
proportion between 2 standard deviations, independent of μ and σ , is given by:
P(Z<2)-P(Z<-2)
=0.977250-0.022750=0.954500=0.95 (to two places of decimal)
