12 ribbons
p.s: im in 7th grade so you can trust me
First you have to have the absolute value isolated so the 2 has to be divided. Then set up the two cases and solve.
20−6√3
Step by step Explanation:
√12+4√25−√108−1/4 √192
2√3+4×5-√108-2√3
2√3+20-√108-2√3
20−6√3