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Svetradugi [14.3K]
3 years ago
5

ME AJUDEM PFV!!O valor da expressão (NA FOTO)simplificada é:

Mathematics
1 answer:
koban [17]3 years ago
7 0

D) 16.

Espero que esto ayude hermano.

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Is there a faster way to find GCF of large numbers e.g 828 and 529.
Sunny_sXe [5.5K]
You can use prime factorization to find the GCF of a set of numbers. This often works better for large numbers, where generating lists of all factors can be time-consuming.
Here’s how to find the GCF of a set of numbers using prime factorization:
* List the prime factors of each number.
* Circle every common prime factor — that is, every prime factor that’s a factor of every number in the set.
* Multiply all the circled numbers.
The result is the GCF.
For example, suppose you want to find the GCF of 28, 42, and 70. Step 1 says to list the prime factors of each number. Step 2 says to circle every prime factor that’s common to all three numbers (as shown in the following figure).
As you can see, the numbers 2 and 7 are common factors of all three numbers. Multiply these circled numbers together:
2 · 7 = 14
Thus, the GCF of 28, 42, and 70 is 14.

5 0
2 years ago
5s + 2z = 1.32 <br> 3s + 1z = 0.75 <br> what would the answer be?
Sphinxa [80]

Answer:                                                                    

Step-by-step explanation:

7 0
3 years ago
You and a friend are baking cookies. You ask how much water she added to the batter and she says "15" What is wrong with her ans
REY [17]
Nothing is writing with her answer
8 0
2 years ago
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Put in order from least to greatest 65, 34, -50, 28, -64, -45​
PIT_PIT [208]
-64, -50, -45, 28, 34, 65
7 0
3 years ago
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A bee flies 6 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 12 minutes, and then fli
AysviL [449]

Remark

You have to do a little subtracting and a little interpreting to get the answer. First you must assume that the bee travels in a straight line. This is math so we can assume this is true, although thousands would disagree.

Second you must assume that because it is loaded with nectar that it travels at a slower rate (not an unreasonable assumption).

Third you have to assume that the distance there is the same distance as coming back. Again this is math. We can make this assumption.

Find the travelling time.

The bee spends 12 minutes hunting down the nectar in the flowerbed. Since it was away from the hive for a total of 16 minutes, the travelling time is

16min - 12min = 4 min

Convert the Minutes to seconds.

1 minute = 60 seconds

4 minutes = 4*60 = 240 seconds.

Find the time each way.

The total time is 240 seconds, but it is not divided evenly.

Let the time there = t

Let the time back = 240 - t

The distances are the same.

r = 6 m/s

r1 = 4 m/s

t1 = t

t2 = 240 - t

dthere = dback

d = rate * time

6 m/s *t = 4 m/s (240 - t)      Remove the brackets on the right.

6 * t = 4*240 - 4t                  Combine the like terms on the right.

6t = 960 - 4t                         Add 4t to both sides

6t + 4t = 960 - 4t + 4t          Combine

10t = 960                              Divide both sides by 10

10t/10 = 960/10                    Do the division

t = 96                                    Time going to the flower bed

Find the distance

d = ?

r = 6 m/s

t = 96 second

d = r*t

d = 6 * 96 = 576 feet Answer


3 0
2 years ago
Read 2 more answers
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