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Rudik [331]
3 years ago
11

Yes, line L' is now the same as L.

Mathematics
1 answer:
Viefleur [7K]3 years ago
6 0
I’m pretty sure it’s No because parrallel lines are straight and it looks like nothing changes between the ls, sorry if this didn’t help
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Please answer quick. I will mark brainliest
Elena L [17]

Answer:

a=5

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Take a bear and have a nice day.

5 0
3 years ago
Which values of a, b, and c represent the answer in simplest form?<br> 7/9 / 4/9
satela [25.4K]
1 3/4 the answer is
8 0
3 years ago
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What is the answer please 2(4 + 2z) =
Alika [10]

Answer: It would be 8+4z  because you can't add a variable.

4 0
3 years ago
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Consider the equation.
babunello [35]

Answer:

If you use the addition property of equality, what number would you add to both sides of the equal sign to isolate the variable?

You would subtract 5/7 from both sides of the equation

What is the solution?

x = 26/7 or 3 and 5/7

Step-by-step explanation:

x + 5/7 = 31/7

Subtract 5/7 from both sides of the equation:

x + 5/7 - 5/7 = 31/7 - 5/7

x = 26/7

6 0
3 years ago
Read 2 more answers
In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24
Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.238\\H_A: p > 0.238

This is a one-tailed(right) test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

4 0
4 years ago
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