9514 1404 393
Answer:
945x^3·y^16
Step-by-step explanation:
The 5th term will be ...
C(7,4)(3x)^3(y^4)^4 = 35·27·x^3·y^(4·4)
= 945x^3·y^16
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The coefficients of the expansion are C(n, k) where n is the exponent of the binomial, and k+1 is the term number. This is n!/(k!(n-k)!). The general (k-th) term of the expansion (a+b)^n is C(n, k)a^(n-k)b^(k) where k ranges from 0 to n.
{1,6}
the second box is always where the y values/range are
What are the numbers?
