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3 years ago

I need help now :) ...........

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

Step-by-step explanation:

-2x² + 5x - 3 - (-7 - 9x + 5x²)

= -2x² + 5x - 3 + 7 + 9x - 5x²

= -7x² + 14x + 4.

Hence the coefficient of the x term is 14.

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Consider the graph shown, which function eventually exceeds the other functions? A) y = 2x B) y = x2 C) y = 2x D) cannot be dete

nirvana33 [79]

Answer:

All of these are the same. I would say D as theya re the same.

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3 years ago

Write the equation of the line in point-slope form that passes through (5, -1) and has a slope of 2/3

kolezko [41]

Answer:

y-(-1)=2/3(x-5)

Step-by-step explanation:

Point slope form is

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3 years ago

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5 5/8 as an improper fraction

(8*5 +5) /8 = 45/8

45/8 divided by 1/4 =

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3 years ago

Kate has some dimes and quarters. if she has 1919 coins worth a total of $2.95, how many of each type of coin does she have?

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3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago