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Lena [83]
3 years ago
13

Dartmouth Assessment Centre screens and trains employees for a computer assembly firm in Halifax. The progress of all trainees i

s tracked and those not showing the proper progress are moved to less demanding programs. By the tenth repetition, trainees must be able to complete the assembly task in 1 hour or less. Torri Olson-Alves has just spent 5 hours on the fourth unit and 4 hours completing her eighth unit, while another trainee, Julie Burgmeier, took 4 hours on the third and 3 hours on the sixth unit. Should you encourage either or both of the trainees to continue? Why?
Business
1 answer:
alexdok [17]3 years ago
3 0

Answer:

Discourage Torri from continuing. Encourage Julie to continue.

Explanation:

The progress of all trainees is tracked. Those not showing good progress are moved to less demanding programs. This means that there is hope of still doing/getting a job, if they don't pass this test.

REQUIREMENT: By the 10th time doing the test, trainees must be able to complete the task in a maximum of 1 hour.

1st Trainee: Torri Olson-Alves

5 hours on Unit 4;   4 hours on Unit 8

Should Torri be encouraged to continue? NO.

There are 10 units or repetitions in all. If Torri spends 5 hours on Unit 4 and spends 4 hours on Unit 8, then Torri is slow or isn't making much progress. After 4 repetitions, her marginal product only increased by an hour. She most likely won't make it to 1 hour by the 10th repetition.

2nd Trainee: Julie Burgmeier

4 hours on Unit 3;   3 hours on Unit 6

Should Julie be encouraged to continue? YES.

Julie makes a progress of 1 hour after 3 repetitions. We can predict that after another 3 repetitions (on Unit 9) progress would be made again and by Unit 10, she would have met the required benchmark.

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\boldsymbol{\mathbf{P(F) = \frac{Total people with favorable responses}{Total people in the survey}}}

\boldsymbol{\mathbf{P(F) = \frac{62}{100}}}

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\boldsymbol{\mathbf{P(F or UF) = P(F) + P(UF)}}

\boldsymbol{\mathbf{P(F or UF) = \frac{62}{100} + \frac{38}{100} = \frac{100}{100}=1}}


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